AQA S1 2014 June — Question 6 14 marks

Exam BoardAQA
ModuleS1 (Statistics 1)
Year2014
SessionJune
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Distribution
TypeMultiple independent binomial calculations
DifficultyModerate -0.3 This is a straightforward S1 binomial distribution question requiring standard calculations: (a) direct use of binomial probability formula, (b) cumulative probability lookups from tables, and (c) basic comparison of sample statistics with theoretical mean/variance. All parts are routine applications of textbook methods with no problem-solving insight required, making it slightly easier than average.
Spec2.04b Binomial distribution: as model B(n,p)2.04c Calculate binomial probabilities

6 The probability that an online order from a supermarket chain has at least one item missing when delivered is 0.06 . Online orders are 'incomplete' if they contain substitute items and/or have at least one item missing when delivered. The probability that an order is incomplete is 0.15 .
  1. Calculate the probability that exactly 2 out of a random sample of 26 online orders have at least one item missing when delivered.
  2. Determine the probability that the number of incomplete orders in a random sample of 50 online orders is:
    1. fewer than 10 ;
    2. more than 5;
    3. more than 6 but fewer than 12 .
  3. Farokh, the manager of one of the supermarket's stores, examines 50 randomly selected online orders from each of a random sample of 100 of the store's customers. He records, for each of the 50 orders, the number, \(x\), that were incomplete. His summarised results, correct to three significant figures, for the 100 customers selected are $$\bar { x } = 4.33 \text { and } s ^ { 2 } = 3.94$$ Use this information to compare the performance of the store managed by Farokh with that of the supermarket chain as a whole.
    [0pt] [5 marks]

Question 6:
Part (a)
AnswerMarks Guidance
AnswerMark Guidance
\(X \sim B(26, 0.06)\)M1 Correct binomial setup
\(P(X=2) = \binom{26}{2}(0.06)^2(0.94)^{24}\)M1 Correct probability calculation
\(= 0.2249...\) awrt \(0.225\)A1
Part (b)
AnswerMarks Guidance
AnswerMark Guidance
\(Y \sim B(50, 0.15)\) Stated or implied
(i) \(P(Y < 10) = P(Y \leq 9)\)M1
\(= 0.9084\) awrt \(0.908\)A1
(ii) \(P(Y > 5) = 1 - P(Y \leq 5)\)M1
\(= 1 - 0.4465 = 0.5535\) awrt \(0.554\)A1
(iii) \(P(6 < Y < 12) = P(Y \leq 11) - P(Y \leq 6)\)M1
\(= 0.9468 - 0.5688 = 0.3780\) awrt \(0.378\)A1
Part (c)
AnswerMarks Guidance
AnswerMark Guidance
Expected value for \(B(50, 0.15)\): \(np = 50 \times 0.15 = 7.5\)B1 Correct mean for chain
\(\bar{x} = 4.33 < 7.5\) so Farokh's store has fewer incomplete orders on averageB1 Comparison of means with context
Expected variance: \(np(1-p) = 50 \times 0.15 \times 0.85 = 6.375\)B1 Correct variance for chain
\(s^2 = 3.94 < 6.375\) so less variability in Farokh's storeB1 Comparison of variances with context
Overall: Farokh's store performs better than the chain as a wholeB1 Conclusion in context
# Question 6:

## Part (a)

| Answer | Mark | Guidance |
|--------|------|----------|
| $X \sim B(26, 0.06)$ | M1 | Correct binomial setup |
| $P(X=2) = \binom{26}{2}(0.06)^2(0.94)^{24}$ | M1 | Correct probability calculation |
| $= 0.2249...$ awrt $0.225$ | A1 | |

## Part (b)

| Answer | Mark | Guidance |
|--------|------|----------|
| $Y \sim B(50, 0.15)$ | | Stated or implied |
| **(i)** $P(Y < 10) = P(Y \leq 9)$ | M1 | |
| $= 0.9084$ awrt $0.908$ | A1 | |
| **(ii)** $P(Y > 5) = 1 - P(Y \leq 5)$ | M1 | |
| $= 1 - 0.4465 = 0.5535$ awrt $0.554$ | A1 | |
| **(iii)** $P(6 < Y < 12) = P(Y \leq 11) - P(Y \leq 6)$ | M1 | |
| $= 0.9468 - 0.5688 = 0.3780$ awrt $0.378$ | A1 | |

## Part (c)

| Answer | Mark | Guidance |
|--------|------|----------|
| Expected value for $B(50, 0.15)$: $np = 50 \times 0.15 = 7.5$ | B1 | Correct mean for chain |
| $\bar{x} = 4.33 < 7.5$ so Farokh's store has fewer incomplete orders on average | B1 | Comparison of means with context |
| Expected variance: $np(1-p) = 50 \times 0.15 \times 0.85 = 6.375$ | B1 | Correct variance for chain |
| $s^2 = 3.94 < 6.375$ so less variability in Farokh's store | B1 | Comparison of variances with context |
| Overall: Farokh's store performs better than the chain as a whole | B1 | Conclusion in context |
6 The probability that an online order from a supermarket chain has at least one item missing when delivered is 0.06 .

Online orders are 'incomplete' if they contain substitute items and/or have at least one item missing when delivered. The probability that an order is incomplete is 0.15 .
\begin{enumerate}[label=(\alph*)]
\item Calculate the probability that exactly 2 out of a random sample of 26 online orders have at least one item missing when delivered.
\item Determine the probability that the number of incomplete orders in a random sample of 50 online orders is:
\begin{enumerate}[label=(\roman*)]
\item fewer than 10 ;
\item more than 5;
\item more than 6 but fewer than 12 .
\end{enumerate}\item Farokh, the manager of one of the supermarket's stores, examines 50 randomly selected online orders from each of a random sample of 100 of the store's customers. He records, for each of the 50 orders, the number, $x$, that were incomplete.

His summarised results, correct to three significant figures, for the 100 customers selected are

$$\bar { x } = 4.33 \text { and } s ^ { 2 } = 3.94$$

Use this information to compare the performance of the store managed by Farokh with that of the supermarket chain as a whole.\\[0pt]
[5 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA S1 2014 Q6 [14]}}