CAIE P2 2013 November — Question 7 10 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2013
SessionNovember
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeDerive equation from integral condition
DifficultyStandard +0.3 This is a straightforward multi-part question requiring standard integration to find area, algebraic rearrangement to derive the iterative form, and mechanical application of fixed-point iteration. All techniques are routine for P2 level with no novel insight required, making it slightly easier than average.
Spec1.08d Evaluate definite integrals: between limits1.09a Sign change methods: locate roots1.09b Sign change methods: understand failure cases1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

7 \includegraphics[max width=\textwidth, alt={}, center]{0900b607-6136-4bf7-a42e-6824d1a21e43-3_451_451_255_845} The diagram shows part of the curve \(y = 8 x + \frac { 1 } { 2 } \mathrm { e } ^ { x }\). The shaded region \(R\) is bounded by the curve and by the lines \(x = 0 , y = 0\) and \(x = a\), where \(a\) is positive. The area of \(R\) is equal to \(\frac { 1 } { 2 }\).
  1. Find an equation satisfied by \(a\), and show that the equation can be written in the form $$a = \sqrt { } \left( \frac { 2 - \mathrm { e } ^ { a } } { 8 } \right)$$
  2. Verify by calculation that the equation \(a = \sqrt { } \left( \frac { 2 - \mathrm { e } ^ { a } } { 8 } \right)\) has a root between 0.2 and 0.3.
  3. Use the iterative formula \(a _ { n + 1 } = \sqrt { } \left( \frac { 2 - \mathrm { e } ^ { a _ { n } } } { 8 } \right)\) to determine this root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

AnswerMarks Guidance
(i) Integrate to obtain terms \(4x^2\) and \(\frac{1}{2}e^t\)B1 + B1
Substitute limits correctlyM1
Obtain correct equation in any form \(4a^2 + \frac{1}{2}e^a - \frac{1}{2} - \frac{1}{2}\)A1
Rearrange to given answer correctlyA1 [5]
(ii) Consider sign of \(\sqrt{\frac{2 - e^a}{8}} - a\), or equivalentM1
Complete the argument correctly with appropriate calculations (\(f(0.2) = 0.112, f(0.3) = -0.015\))A1 [2]
(iii) Use the iterative formula correctly at least onceM1
Obtain final answer 0.29A1
Show sufficient iterations to justify its accuracy to 2 d.p.B1
or show there is a sign change in the interval \((0.285, 0.295)\)[3]
(i) Integrate to obtain terms $4x^2$ and $\frac{1}{2}e^t$ | B1 + B1 |
Substitute limits correctly | M1 |
Obtain correct equation in any form $4a^2 + \frac{1}{2}e^a - \frac{1}{2} - \frac{1}{2}$ | A1 |
Rearrange to given answer correctly | A1 | [5]

(ii) Consider sign of $\sqrt{\frac{2 - e^a}{8}} - a$, or equivalent | M1 |
Complete the argument correctly with appropriate calculations ($f(0.2) = 0.112, f(0.3) = -0.015$) | A1 | [2]

(iii) Use the iterative formula correctly at least once | M1 |
Obtain final answer 0.29 | A1 |
Show sufficient iterations to justify its accuracy to 2 d.p. | B1 |
or show there is a sign change in the interval $(0.285, 0.295)$ | [3]
7\\
\includegraphics[max width=\textwidth, alt={}, center]{0900b607-6136-4bf7-a42e-6824d1a21e43-3_451_451_255_845}

The diagram shows part of the curve $y = 8 x + \frac { 1 } { 2 } \mathrm { e } ^ { x }$. The shaded region $R$ is bounded by the curve and by the lines $x = 0 , y = 0$ and $x = a$, where $a$ is positive. The area of $R$ is equal to $\frac { 1 } { 2 }$.\\
(i) Find an equation satisfied by $a$, and show that the equation can be written in the form

$$a = \sqrt { } \left( \frac { 2 - \mathrm { e } ^ { a } } { 8 } \right)$$

(ii) Verify by calculation that the equation $a = \sqrt { } \left( \frac { 2 - \mathrm { e } ^ { a } } { 8 } \right)$ has a root between 0.2 and 0.3.\\
(iii) Use the iterative formula $a _ { n + 1 } = \sqrt { } \left( \frac { 2 - \mathrm { e } ^ { a _ { n } } } { 8 } \right)$ to determine this root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

\hfill \mbox{\textit{CAIE P2 2013 Q7 [10]}}