AQA C4 2012 June — Question 5 9 marks

Exam BoardAQA
ModuleC4 (Core Mathematics 4)
Year2012
SessionJune
Marks9
PaperDownload PDF ↗
TopicParametric curves and Cartesian conversion
TypeConvert to Cartesian (sin/cos identities)
DifficultyStandard +0.3 This is a standard C4 parametric equations question requiring routine techniques: chain rule for dy/dx, double angle formula (sin 2θ = 2sin θ cos θ), and algebraic manipulation using cos²θ + sin²θ = 1. All steps are predictable textbook methods with no novel insight required, making it slightly easier than average.
Spec1.03g Parametric equations: of curves and conversion to cartesian1.07s Parametric and implicit differentiation

5 A curve is defined by the parametric equations $$x = 2 \cos \theta , \quad y = 3 \sin 2 \theta$$
    1. Show that $$\frac { \mathrm { d } y } { \mathrm {~d} x } = a \sin \theta + b \operatorname { cosec } \theta$$ where \(a\) and \(b\) are integers.
    2. Find the gradient of the normal to the curve at the point where \(\theta = \frac { \pi } { 6 }\).
  1. Show that the cartesian equation of the curve can be expressed as $$y ^ { 2 } = p x ^ { 2 } \left( 4 - x ^ { 2 } \right)$$ where \(p\) is a rational number.

5 A curve is defined by the parametric equations

$$x = 2 \cos \theta , \quad y = 3 \sin 2 \theta$$
\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Show that

$$\frac { \mathrm { d } y } { \mathrm {~d} x } = a \sin \theta + b \operatorname { cosec } \theta$$

where $a$ and $b$ are integers.
\item Find the gradient of the normal to the curve at the point where $\theta = \frac { \pi } { 6 }$.
\end{enumerate}\item Show that the cartesian equation of the curve can be expressed as

$$y ^ { 2 } = p x ^ { 2 } \left( 4 - x ^ { 2 } \right)$$

where $p$ is a rational number.
\end{enumerate}

\hfill \mbox{\textit{AQA C4 2012 Q5 [9]}}