CAIE P2 2012 November — Question 6 7 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2012
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeDefinite integral with logarithmic form
DifficultyModerate -0.8 Part (a) is a straightforward application of exponential integration with a linear coefficient in the exponent. Part (b) is a standard logarithmic integration requiring recognition of the derivative of (3x-1) and simple arithmetic to verify the given answer. Both parts are routine exercises testing basic integration techniques with no problem-solving or novel insight required, making this easier than average.
Spec1.06d Natural logarithm: ln(x) function and properties1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)

6
  1. Find \(\int 4 \mathrm { e } ^ { - \frac { 1 } { 2 } x } \mathrm {~d} x\).
  2. Show that \(\int _ { 1 } ^ { 3 } \frac { 6 } { 3 x - 1 } \mathrm {~d} x = \ln 16\).

AnswerMarks
(a) Obtain integral \(ke^{\frac{x}{2}}\) with any non-zero \(k\)M1
Correct integralA1
[2]
(b) State indefinite integral of the form \(k \ln(3x - 1)\), where \(k = 2, 6\) or \(3\)M1
State correct integral \(2 \ln(3x - 1)\)A1
Substitute limits correctly (must be a function involving a logarithm)M1
Use law for the logarithm of a power or a quotientM1
Obtain given answer correctlyA1
[5]
**(a)** Obtain integral $ke^{\frac{x}{2}}$ with any non-zero $k$ | M1 |
Correct integral | A1 |
| | [2] |

**(b)** State indefinite integral of the form $k \ln(3x - 1)$, where $k = 2, 6$ or $3$ | M1 |
State correct integral $2 \ln(3x - 1)$ | A1 |
Substitute limits correctly (must be a function involving a logarithm) | M1 |
Use law for the logarithm of a power or a quotient | M1 |
Obtain given answer correctly | A1 |
| | [5] |
6
\begin{enumerate}[label=(\alph*)]
\item Find $\int 4 \mathrm { e } ^ { - \frac { 1 } { 2 } x } \mathrm {~d} x$.
\item Show that $\int _ { 1 } ^ { 3 } \frac { 6 } { 3 x - 1 } \mathrm {~d} x = \ln 16$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2012 Q6 [7]}}