Edexcel C3 — Question 5 11 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Functions
TypeTangent to exponential curve
DifficultyModerate -0.3 This is a standard C3 exponential function question covering routine techniques: range identification, finding inverse functions, solving exponential equations, and finding tangent equations. All parts follow textbook procedures with no novel problem-solving required, making it slightly easier than average but still requiring multiple techniques and careful algebraic manipulation.
Spec1.02v Inverse and composite functions: graphs and conditions for existence1.06a Exponential function: a^x and e^x graphs and properties1.06g Equations with exponentials: solve a^x = b1.07j Differentiate exponentials: e^(kx) and a^(kx)1.07m Tangents and normals: gradient and equations

5. $$\mathrm { f } ( x ) = 5 + \mathrm { e } ^ { 2 x - 3 } , \quad x \in \mathbb { R } .$$
  1. State the range of f .
  2. Find an expression for \(\mathrm { f } ^ { - 1 } ( x )\) and state its domain.
  3. Solve the equation \(\mathrm { f } ( x ) = 7\).
  4. Find an equation for the tangent to the curve \(y = \mathrm { f } ( x )\) at the point where \(y = 7\).

(a)
AnswerMarks
\(f(x) > 5\)B1
(b)
AnswerMarks
\(y = 5 + e^{2x - 3}\)M1
\(2x - 3 = \ln(y - 5)\)M1
\(x = \frac{1}{2}[3 + \ln(y - 5)]\)M1
\(\therefore f^{-1}(x) = \frac{1}{2}[3 + \ln(x - 5)], \mathbb{R}, x > 5\)A2
(c)
AnswerMarks
\(x = f^{-1}(7) = \frac{1}{2}(3 + \ln 2)\)M1 A1
(d)
AnswerMarks Guidance
\(f'(x) = 2e^{2x - 3}\)M1
grad \(= 4\)A1
\(\therefore y - 7 = 4[x - \frac{1}{2}(3 + \ln 2)]\)M1 A1
\([y = 4x + 1 - 2\ln 2]\)M1 A1 (11 marks)
**(a)**
$f(x) > 5$ | B1 |

**(b)**
$y = 5 + e^{2x - 3}$ | M1 |
$2x - 3 = \ln(y - 5)$ | M1 |
$x = \frac{1}{2}[3 + \ln(y - 5)]$ | M1 |
$\therefore f^{-1}(x) = \frac{1}{2}[3 + \ln(x - 5)], \mathbb{R}, x > 5$ | A2 |

**(c)**
$x = f^{-1}(7) = \frac{1}{2}(3 + \ln 2)$ | M1 A1 |

**(d)**
$f'(x) = 2e^{2x - 3}$ | M1 |
grad $= 4$ | A1 |
$\therefore y - 7 = 4[x - \frac{1}{2}(3 + \ln 2)]$ | M1 A1 |
$[y = 4x + 1 - 2\ln 2]$ | M1 A1 | (11 marks)
5.

$$\mathrm { f } ( x ) = 5 + \mathrm { e } ^ { 2 x - 3 } , \quad x \in \mathbb { R } .$$

(a) State the range of f .\\
(b) Find an expression for $\mathrm { f } ^ { - 1 } ( x )$ and state its domain.\\
(c) Solve the equation $\mathrm { f } ( x ) = 7$.\\
(d) Find an equation for the tangent to the curve $y = \mathrm { f } ( x )$ at the point where $y = 7$.\\

\hfill \mbox{\textit{Edexcel C3  Q5 [11]}}