Edexcel C3 — Question 6 13 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeSolve equation with inverses
DifficultyStandard +0.3 This is a standard C3 inverse functions question covering routine techniques: finding range, sketching reflections in y=x, deriving inverse algebraically, and solving f^(-1)(x)=g(x). Part (e) requires solving a quadratic equation but follows directly from substituting the expressions. All steps are textbook exercises with no novel insight required, making it slightly easier than average.
Spec1.02m Graphs of functions: difference between plotting and sketching1.02n Sketch curves: simple equations including polynomials1.02u Functions: definition and vocabulary (domain, range, mapping)1.02v Inverse and composite functions: graphs and conditions for existence

6. The function f is defined by $$\mathrm { f } ( x ) \equiv 3 - x ^ { 2 } , \quad x \in \mathbb { R } , \quad x \geq 0 .$$
  1. State the range of f.
  2. Sketch the graphs of \(y = \mathrm { f } ( x )\) and \(y = \mathrm { f } ^ { - 1 } ( x )\) on the same diagram.
  3. Find an expression for \(\mathrm { f } ^ { - 1 } ( x )\) and state its domain. The function g is defined by $$\mathrm { g } ( x ) \equiv \frac { 8 } { 3 - x } , \quad x \in \mathbb { R } , \quad x \neq 3 .$$
  4. Evaluate \(\mathrm { fg } ( - 3 )\).
  5. Solve the equation $$\mathrm { f } ^ { - 1 } ( x ) = \mathrm { g } ( x ) .$$

AnswerMarks Guidance
(a) \(f(x) \leq 3\)B1
(b) [Graph showing \(y = f(x)\) and \(y = f^{-1}(x)\) reflected in a line, with appropriate shape]B3
(c) \(y = 3 - x^2\)M1
\(x^2 = 3 - y\)M1
\(x = \pm\sqrt{3-y}\)M1
\(f^{-1}(x) = \sqrt{3-x}, x \in \mathbb{R}, x \leq 3\)M1 A2
(d) \(= f(\frac{4}{3}) = \frac{11}{9}\)M1 A1
(e) \(\sqrt{3-x} = \frac{8}{3-x}\)M1
\(3 - x = \frac{64}{(3-x)^2}\)M1
\((3-x)^3 = 64\)M1
\(3 - x = 4\)M1
\(x = -1\)A1 (13)
**(a)** $f(x) \leq 3$ | B1 |

**(b)** [Graph showing $y = f(x)$ and $y = f^{-1}(x)$ reflected in a line, with appropriate shape] | B3 |

**(c)** $y = 3 - x^2$ | M1 |
$x^2 = 3 - y$ | M1 |
$x = \pm\sqrt{3-y}$ | M1 |
$f^{-1}(x) = \sqrt{3-x}, x \in \mathbb{R}, x \leq 3$ | M1 A2 |

**(d)** $= f(\frac{4}{3}) = \frac{11}{9}$ | M1 A1 |

**(e)** $\sqrt{3-x} = \frac{8}{3-x}$ | M1 |
$3 - x = \frac{64}{(3-x)^2}$ | M1 |
$(3-x)^3 = 64$ | M1 |
$3 - x = 4$ | M1 |
$x = -1$ | A1 | (13)
6. The function f is defined by

$$\mathrm { f } ( x ) \equiv 3 - x ^ { 2 } , \quad x \in \mathbb { R } , \quad x \geq 0 .$$
\begin{enumerate}[label=(\alph*)]
\item State the range of f.
\item Sketch the graphs of $y = \mathrm { f } ( x )$ and $y = \mathrm { f } ^ { - 1 } ( x )$ on the same diagram.
\item Find an expression for $\mathrm { f } ^ { - 1 } ( x )$ and state its domain.

The function g is defined by

$$\mathrm { g } ( x ) \equiv \frac { 8 } { 3 - x } , \quad x \in \mathbb { R } , \quad x \neq 3 .$$
\item Evaluate $\mathrm { fg } ( - 3 )$.
\item Solve the equation

$$\mathrm { f } ^ { - 1 } ( x ) = \mathrm { g } ( x ) .$$
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3  Q6 [13]}}