CAIE P2 2011 November — Question 5 6 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2011
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeMultiple angle equations
DifficultyStandard +0.3 This is a straightforward multiple angle trigonometric equation requiring the identity sec²x = 1 + tan²x to convert to a quadratic in tan 2θ, then solving and finding angles in the given range. While it involves reciprocal trig functions and double angles, the method is standard and mechanical with no novel insight required, making it slightly easier than average.
Spec1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.05o Trigonometric equations: solve in given intervals

5 Solve the equation \(5 \sec ^ { 2 } 2 \theta = \tan 2 \theta + 9\), giving all solutions in the interval \(0 ^ { \circ } \leqslant \theta \leqslant 180 ^ { \circ }\).

AnswerMarks Guidance
Use trig identity correctly to obtain a quadratic in \(\tan 2\theta\)M1
Solve the quadratic correctlyM1
Obtain \(\tan 2\theta = 1\) or \(-\frac{4}{5}\)A1
Obtain one correct answerA1
Carry out correct method for second answer from either rootM1
Obtain remaining 3 answers from \(22.5°, 112.5°, 70.7°, 160.7°\) and no others in the range [Ignore answers outside the given range]A1 [6]
Use trig identity correctly to obtain a quadratic in $\tan 2\theta$ | M1 |
Solve the quadratic correctly | M1 |
Obtain $\tan 2\theta = 1$ or $-\frac{4}{5}$ | A1 |
Obtain one correct answer | A1 |
Carry out correct method for second answer from either root | M1 |
Obtain remaining 3 answers from $22.5°, 112.5°, 70.7°, 160.7°$ and no others in the range [Ignore answers outside the given range] | A1 | [6]
5 Solve the equation $5 \sec ^ { 2 } 2 \theta = \tan 2 \theta + 9$, giving all solutions in the interval $0 ^ { \circ } \leqslant \theta \leqslant 180 ^ { \circ }$.

\hfill \mbox{\textit{CAIE P2 2011 Q5 [6]}}