CAIE P2 2011 November — Question 8 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2011
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyModerate -0.3 This is a standard harmonic form question requiring routine application of R cos(θ + α) = R cos α cos θ - R sin α sin θ, solving a trigonometric equation using the result, and recognizing that the minimum of the related expression is simply -3R. All steps are textbook procedures with no novel insight required, making it slightly easier than average.
Spec1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

8
  1. Express \(5 \cos \theta - 3 \sin \theta\) in the form \(R \cos ( \theta + \alpha )\), where \(R > 0\) and \(0 ^ { \circ } < \alpha < 90 ^ { \circ }\), giving the exact value of \(R\) and the value of \(\alpha\) correct to 2 decimal places.
  2. Hence solve the equation $$5 \cos \theta - 3 \sin \theta = 4$$ giving all solutions in the interval \(0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }\).
  3. Write down the least value of \(15 \cos \theta - 9 \sin \theta\) as \(\theta\) varies.

AnswerMarks Guidance
(i) State \(R = \sqrt{34}\)B1
Use trig formula to find \(a\)M1
Obtain \(\alpha = 30.96°\) with no errors seenA1 [3]
(ii) Carry out evaluation of \(\cos\left(\frac{4}{R}\right)\) (\(\approx 46.6861°\) or \(313.3139°\))M1
Obtain answer \(15.7°\)A1
Carry out correct method for second answerM1
Obtain answer \(282.3°\) or \(282.4°\) and no others in the rangeA1 [4]
(iii) State \(-3\sqrt{34}\) (\(= -3R\))B1√ [1]
**(i)** State $R = \sqrt{34}$ | B1 |
Use trig formula to find $a$ | M1 |
Obtain $\alpha = 30.96°$ with no errors seen | A1 | [3] |

**(ii)** Carry out evaluation of $\cos\left(\frac{4}{R}\right)$ ($\approx 46.6861°$ or $313.3139°$) | M1 |
Obtain answer $15.7°$ | A1 |
Carry out correct method for second answer | M1 |
Obtain answer $282.3°$ or $282.4°$ and no others in the range | A1 | [4] |

**(iii)** State $-3\sqrt{34}$ ($= -3R$) | B1√ | [1] |
8 (i) Express $5 \cos \theta - 3 \sin \theta$ in the form $R \cos ( \theta + \alpha )$, where $R > 0$ and $0 ^ { \circ } < \alpha < 90 ^ { \circ }$, giving the exact value of $R$ and the value of $\alpha$ correct to 2 decimal places.\\
(ii) Hence solve the equation

$$5 \cos \theta - 3 \sin \theta = 4$$

giving all solutions in the interval $0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }$.\\
(iii) Write down the least value of $15 \cos \theta - 9 \sin \theta$ as $\theta$ varies.

\hfill \mbox{\textit{CAIE P2 2011 Q8 [8]}}