CAIE P2 2011 November — Question 7 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2011
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicParametric differentiation
TypeTangent parallel to axis condition
DifficultyStandard +0.3 This is a straightforward parametric differentiation question requiring the chain rule (dy/dx = dy/dt รท dx/dt), product rule for dy/dt, and solving dy/dx = 0. All techniques are standard P2 content with no novel insight required, making it slightly easier than average.
Spec1.07m Tangents and normals: gradient and equations1.07s Parametric and implicit differentiation

7 The parametric equations of a curve are $$x = \mathrm { e } ^ { 3 t } , \quad y = t ^ { 2 } \mathrm { e } ^ { t } + 3$$
  1. Show that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { t ( t + 2 ) } { 3 \mathrm { e } ^ { 2 t } }\).
  2. Show that the tangent to the curve at the point \(( 1,3 )\) is parallel to the \(x\)-axis.
  3. Find the exact coordinates of the other point on the curve at which the tangent is parallel to the \(x\)-axis.

AnswerMarks Guidance
(i) Use product rule to differentiate \(v\)M1
Obtain correct derivative in any form in \(t\) for \(y\)A1
Use \(\frac{dy}{dx} = \frac{dy}{dt} \div \frac{dx}{dt}\)M1
Obtain given answer correctlyA1 [4]
(ii) State \(t = 0\)M1
State that \(\frac{dy}{dx} = 0\) and make correct conclusionA1 [2]
(iii) Substitute \(t = -2\) into equation for \(x\) or \(y\)M1
Obtain \((e^{-6}, 4e^{-3}+3)\)A1 [2]
**(i)** Use product rule to differentiate $v$ | M1 |

Obtain correct derivative in any form in $t$ for $y$ | A1 |

Use $\frac{dy}{dx} = \frac{dy}{dt} \div \frac{dx}{dt}$ | M1 |

Obtain given answer correctly | A1 | [4]

**(ii)** State $t = 0$ | M1 |

State that $\frac{dy}{dx} = 0$ and make correct conclusion | A1 | [2]

**(iii)** Substitute $t = -2$ into equation for $x$ or $y$ | M1 |

Obtain $(e^{-6}, 4e^{-3}+3)$ | A1 | [2]
7 The parametric equations of a curve are

$$x = \mathrm { e } ^ { 3 t } , \quad y = t ^ { 2 } \mathrm { e } ^ { t } + 3$$

(i) Show that $\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { t ( t + 2 ) } { 3 \mathrm { e } ^ { 2 t } }$.\\
(ii) Show that the tangent to the curve at the point $( 1,3 )$ is parallel to the $x$-axis.\\
(iii) Find the exact coordinates of the other point on the curve at which the tangent is parallel to the $x$-axis.

\hfill \mbox{\textit{CAIE P2 2011 Q7 [8]}}