CAIE P2 2011 November — Question 2 5 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2011
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeDefinite integral with logarithmic form
DifficultyModerate -0.8 This is a straightforward application of the standard integral ∫(1/x)dx = ln|x| with a linear substitution (4x+1). Students need to recognize the reverse chain rule pattern, integrate to get (1/2)ln|4x+1|, then evaluate at the limits and simplify using log laws. While it requires careful algebraic manipulation of logarithms, it's a routine textbook exercise with no problem-solving insight needed, making it easier than average.
Spec1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)1.08d Evaluate definite integrals: between limits

2 Show that \(\int _ { 2 } ^ { 6 } \frac { 2 } { 4 x + 1 } \mathrm {~d} x = \ln \frac { 5 } { 3 }\).

AnswerMarks Guidance
Integrate and obtain term of the form \(k\ln(4x+1)\)M1
State correct term \(\frac{1}{2}\ln(4x+1)\)A1
Substitute limits correctlyM1
Use law for the logarithm of a quotient or a powerM1
Obtain given answer correctlyA1 [5]
Integrate and obtain term of the form $k\ln(4x+1)$ | M1 |

State correct term $\frac{1}{2}\ln(4x+1)$ | A1 |

Substitute limits correctly | M1 |

Use law for the logarithm of a quotient or a power | M1 |

Obtain given answer correctly | A1 | [5]
2 Show that $\int _ { 2 } ^ { 6 } \frac { 2 } { 4 x + 1 } \mathrm {~d} x = \ln \frac { 5 } { 3 }$.

\hfill \mbox{\textit{CAIE P2 2011 Q2 [5]}}