Edexcel C2 — Question 3 7 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLaws of Logarithms
TypeSolve using substitution or auxiliary variable
DifficultyModerate -0.3 This is a straightforward C2 logarithm question requiring basic log laws (quotient, power, and root rules) and simple algebraic manipulation. Part (a) guides students through the substitution, making part (b) routine. The multi-step nature and substitution technique place it slightly below average difficulty, but it remains a standard textbook exercise with no novel insight required.
Spec1.06f Laws of logarithms: addition, subtraction, power rules

3. (a) Given that \(y = \log _ { 2 } x\), find expressions in terms of \(y\) for
  1. \(\quad \log _ { 2 } \left( \frac { x } { 2 } \right)\),
  2. \(\log _ { 2 } ( \sqrt { x } )\).
    (b) Hence, or otherwise, solve the equation $$2 \log _ { 2 } \left( \frac { x } { 2 } \right) + \log _ { 2 } ( \sqrt { x } ) = 8$$

AnswerMarks Guidance
(a) (i) \(= \log_2 x - \log_2 2 = y - 1\)M1 A1
(ii) \(= \log_2 x^3 = \frac{1}{2}\log_2 x = \frac{1}{2}y\)M1 A1
(b) \(2(y-1) + \frac{1}{2}y = 8\)M1
\(y = 4\)
\(\log_2 x = 4, \quad x = 2^4 = 16\)M1 A1 (7)
**(a)** (i) $= \log_2 x - \log_2 2 = y - 1$ | M1 A1 |

(ii) $= \log_2 x^3 = \frac{1}{2}\log_2 x = \frac{1}{2}y$ | M1 A1 |

**(b)** $2(y-1) + \frac{1}{2}y = 8$ | M1 |

$y = 4$ | |

$\log_2 x = 4, \quad x = 2^4 = 16$ | M1 A1 | **(7)**
3. (a) Given that $y = \log _ { 2 } x$, find expressions in terms of $y$ for
\begin{enumerate}[label=(\roman*)]
\item $\quad \log _ { 2 } \left( \frac { x } { 2 } \right)$,
\item $\log _ { 2 } ( \sqrt { x } )$.\\
(b) Hence, or otherwise, solve the equation

$$2 \log _ { 2 } \left( \frac { x } { 2 } \right) + \log _ { 2 } ( \sqrt { x } ) = 8$$
\end{enumerate}

\hfill \mbox{\textit{Edexcel C2  Q3 [7]}}