CAIE P2 2010 November — Question 3 6 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2010
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFactor & Remainder Theorem
TypePolynomial with equal remainders
DifficultyModerate -0.8 This is a straightforward application of the Remainder Theorem requiring students to set p(-1) = p(2) to find a constant, then verify a factor and perform polynomial division. The question involves only routine algebraic manipulation with no problem-solving insight needed, making it easier than average but not trivial since it requires understanding the Remainder Theorem concept and careful arithmetic across multiple steps.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem

3 The polynomial \(x ^ { 3 } + 4 x ^ { 2 } + a x + 2\), where \(a\) is a constant, is denoted by \(\mathrm { p } ( x )\). It is given that the remainder when \(\mathrm { p } ( x )\) is divided by ( \(x + 1\) ) is equal to the remainder when \(\mathrm { p } ( x )\) is divided by ( \(x - 2\) ).
  1. Find the value of \(a\).
  2. When \(a\) has this value, show that \(( x - 1 )\) is a factor of \(\mathrm { p } ( x )\) and find the quotient when \(\mathrm { p } ( x )\) is divided by \(( x - 1 )\).

(i)
AnswerMarks Guidance
Substitute \(x = -1\) OR \(x = 2\) correctlyM1
Equate remainders to obtain correct equation \(5 - a = 26 + 2a\) or equivalentA1
Obtain \(a = -7\)A1 [3]
(ii)
AnswerMarks Guidance
Attempt division by \(x - 1\) and reach a partial quotient of \(x^2 + kx\)M1
Obtain quotient \(x^2 + 5x - 2\)A1
EITHER Show remainder is zero OR substitute \(x = 1\) to obtain zeroB1 [3]
**(i)**

| Substitute $x = -1$ OR $x = 2$ correctly | M1 |
| Equate remainders to obtain correct equation $5 - a = 26 + 2a$ or equivalent | A1 |
| Obtain $a = -7$ | A1 | [3] |

**(ii)**

| Attempt division by $x - 1$ and reach a partial quotient of $x^2 + kx$ | M1 |
| Obtain quotient $x^2 + 5x - 2$ | A1 |
| EITHER Show remainder is zero OR substitute $x = 1$ to obtain zero | B1 | [3] |
3 The polynomial $x ^ { 3 } + 4 x ^ { 2 } + a x + 2$, where $a$ is a constant, is denoted by $\mathrm { p } ( x )$. It is given that the remainder when $\mathrm { p } ( x )$ is divided by ( $x + 1$ ) is equal to the remainder when $\mathrm { p } ( x )$ is divided by ( $x - 2$ ).\\
(i) Find the value of $a$.\\
(ii) When $a$ has this value, show that $( x - 1 )$ is a factor of $\mathrm { p } ( x )$ and find the quotient when $\mathrm { p } ( x )$ is divided by $( x - 1 )$.

\hfill \mbox{\textit{CAIE P2 2010 Q3 [6]}}