Edexcel C2 — Question 9 13 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFactor & Remainder Theorem
TypeExpress as product with specific form
DifficultyStandard +0.3 This is a standard C2 factor theorem question with routine steps: evaluate f(1) to find a factor, perform polynomial division to factorize completely, sketch a cubic with a repeated root, and integrate between roots. All techniques are textbook exercises requiring no novel insight, though the multi-part structure and integration at the end place it slightly above average difficulty.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02n Sketch curves: simple equations including polynomials1.08e Area between curve and x-axis: using definite integrals

9. $$f ( x ) = x ^ { 3 } - 9 x ^ { 2 } + 24 x - 16 .$$
  1. Evaluate \(\mathrm { f } ( 1 )\) and hence state a linear factor of \(\mathrm { f } ( x )\).
  2. Show that \(\mathrm { f } ( x )\) can be expressed in the form $$\mathrm { f } ( x ) = ( x + p ) ( x + q ) ^ { 2 } ,$$ where \(p\) and \(q\) are integers to be found.
  3. Sketch the curve \(y = \mathrm { f } ( x )\).
  4. Using integration, find the area of the region enclosed by the curve \(y = \mathrm { f } ( x )\) and the \(x\)-axis.

AnswerMarks Guidance
(a) \(f(1) = 1 - 9 + 24 - 16 = 0\)B1
\(\therefore (x-1)\) is a factor of \(f(x)\)B1
(b) Polynomial long division:M1 A1
\(f(x) = (x-1)(x^2 - 8x + 16)\)M1 A1
\(f(x) = (x-1)(x-4)^2\)[\(p = -1, q = -4\)] M1 A1
(c) Sketch showing: curve passing through origin, local maximum between \(0\) and \(4\), touching \(x\)-axis at \(x = 4\), and increasing after.B2
(d) \(= \int_1^4 (x^3 - 9x^2 + 24x - 16) \, dx\)M1
\(= \left[\frac{1}{4}x^4 - 3x^3 + 12x^2 - 16x\right]_1^4\)M1 A2
\(= [(64 - 192 + 192 - 64) - (-\frac{1}{4} - 3 + 12 - 16)]\)M1
\(= 6\frac{1}{4}\)A1 (13 marks)
Total: 75 marks
**(a)** $f(1) = 1 - 9 + 24 - 16 = 0$ | B1 |
$\therefore (x-1)$ is a factor of $f(x)$ | B1 |

**(b)** Polynomial long division: | M1 A1 |
$f(x) = (x-1)(x^2 - 8x + 16)$ | M1 A1 |
$f(x) = (x-1)(x-4)^2$ | [$p = -1, q = -4$] | M1 A1 |

**(c)** Sketch showing: curve passing through origin, local maximum between $0$ and $4$, touching $x$-axis at $x = 4$, and increasing after. | B2 |

**(d)** $= \int_1^4 (x^3 - 9x^2 + 24x - 16) \, dx$ | M1 |
$= \left[\frac{1}{4}x^4 - 3x^3 + 12x^2 - 16x\right]_1^4$ | M1 A2 |
$= [(64 - 192 + 192 - 64) - (-\frac{1}{4} - 3 + 12 - 16)]$ | M1 |
$= 6\frac{1}{4}$ | A1 | **(13 marks)**

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**Total: 75 marks**
9.

$$f ( x ) = x ^ { 3 } - 9 x ^ { 2 } + 24 x - 16 .$$
\begin{enumerate}[label=(\alph*)]
\item Evaluate $\mathrm { f } ( 1 )$ and hence state a linear factor of $\mathrm { f } ( x )$.
\item Show that $\mathrm { f } ( x )$ can be expressed in the form

$$\mathrm { f } ( x ) = ( x + p ) ( x + q ) ^ { 2 } ,$$

where $p$ and $q$ are integers to be found.
\item Sketch the curve $y = \mathrm { f } ( x )$.
\item Using integration, find the area of the region enclosed by the curve $y = \mathrm { f } ( x )$ and the $x$-axis.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C2  Q9 [13]}}