AQA C2 2016 June — Question 7 8 marks

Exam BoardAQA
ModuleC2 (Core Mathematics 2)
Year2016
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeStandard product of two binomials
DifficultyStandard +0.3 Part (a) is routine binomial expansion with small positive integer power requiring calculation of three coefficients. Part (b) requires multiplying two binomial expansions and collecting terms for x^10, which is a standard technique but involves more careful bookkeeping across multiple terms. Overall slightly easier than average due to straightforward application of binomial theorem with no novel insight required.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

7
  1. The expression \(( 1 - 2 x ) ^ { 5 }\) can be written in the form $$1 + p x + q x ^ { 2 } + r x ^ { 3 } + 80 x ^ { 4 } - 32 x ^ { 5 }$$ By using the binomial expansion, or otherwise, find the values of the coefficients \(p , q\) and \(r\).
  2. Find the value of the coefficient of \(x ^ { 10 }\) in the expansion of \(( 1 - 2 x ) ^ { 5 } ( 2 + x ) ^ { 7 }\).
    [0pt] [5 marks]

AnswerMarks Guidance
(a)\(p = -10; \quad q = 40; \quad r = -80\) B1, B1, B1
(b)\((2 + x)^7 = ......... + mx^5 + nx^6 + x^7\) M1
(b)\(m = 84, \quad n = 14\) A1
(b)Coefficients of \(x^{10}\) terms in expansion of \((1 - 2x)^7(2 + x)^7\) are \(-32m + 80n + r\) m1
(b)Coeff. of \(x^{10} = (-32)(84) + (80)(14) + r = -2688 + 1120 + r = -1568 + r\) A1F
(b)Coeff. of \(x^{10} = -1648\) A1
Total8
(a) | $p = -10; \quad q = 40; \quad r = -80$ | B1, B1, B1 | 3 marks | Accept correct embedded values for p, q and r within the expansion
(b) | $(2 + x)^7 = ......... + mx^5 + nx^6 + x^7$ | M1 | Attempting to find **at least two of** $x^5$ term, $x^6$ term, $x^7$ term in the expansion of $(2 + x)^7$
(b) | $m = 84, \quad n = 14$ | A1 | Either correct. (M1 must be scored). PI by later correct work
(b) | Coefficients of $x^{10}$ terms in expansion of $(1 - 2x)^7(2 + x)^7$ are $-32m + 80n + r$ | m1 | Identifying at least two of the three products $-32m, 80n, r$ that give $x^{10}$ terms
(b) | Coeff. of $x^{10} = (-32)(84) + (80)(14) + r = -2688 + 1120 + r = -1568 + r$ | A1F | **Only** if c's value of r in (a). If not shown in any of these forms, can be implied by final answer which matches correct evaluation of $(-1568+\text{c's } r)$
(b) | Coeff. of $x^{10} = -1648$ | A1 | 5 marks | $-1648$ or left as ' $-1648 x^{10}$ '. Ignore other powers of x terms
| **Total** | **8** |

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7
\begin{enumerate}[label=(\alph*)]
\item The expression $( 1 - 2 x ) ^ { 5 }$ can be written in the form

$$1 + p x + q x ^ { 2 } + r x ^ { 3 } + 80 x ^ { 4 } - 32 x ^ { 5 }$$

By using the binomial expansion, or otherwise, find the values of the coefficients $p , q$ and $r$.
\item Find the value of the coefficient of $x ^ { 10 }$ in the expansion of $( 1 - 2 x ) ^ { 5 } ( 2 + x ) ^ { 7 }$.\\[0pt]
[5 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA C2 2016 Q7 [8]}}