1 The triangle \(A B C\), shown in the diagram, is such that \(A C = 9 \mathrm {~cm} , B C = 10 \mathrm {~cm}\), angle \(A B C = 54 ^ { \circ }\) and the acute angle \(B A C = \theta\).
- Show that \(\theta = 64 ^ { \circ }\), correct to the nearest degree.
- Calculate the area of triangle \(A B C\), giving your answer to the nearest square centimetre.