Solve the equation \(\tan x = - 3\) in the interval \(0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }\), giving your answers to the nearest degree.
Given that
$$7 \sin ^ { 2 } \theta + \sin \theta \cos \theta = 6$$
show that
$$\tan ^ { 2 } \theta + \tan \theta - 6 = 0$$
Hence solve the equation \(7 \sin ^ { 2 } \theta + \sin \theta \cos \theta = 6\) in the interval \(0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }\), giving your answers to the nearest degree.
(4 marks)