CAIE P2 2007 November — Question 2 5 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2007
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeFind equation satisfied by limit
DifficultyStandard +0.3 This is a straightforward fixed point iteration question requiring routine application of the formula (part i) and simple algebraic manipulation to find the limit equation by setting x_{n+1} = x_n = α (part ii). The equation 3α³ = 2α³ + 12 is easily solved. While it involves multiple steps, each is standard procedure with no novel insight required, making it slightly easier than average.
Spec1.02f Solve quadratic equations: including in a function of unknown1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

2 The sequence of values given by the iterative formula $$x _ { n + 1 } = \frac { 2 x _ { n } } { 3 } + \frac { 4 } { x _ { n } ^ { 2 } }$$ with initial value \(x _ { 1 } = 2\), converges to \(\alpha\).
  1. Use this iterative formula to determine \(\alpha\) correct to 2 decimal places, giving the result of each iteration to 4 decimal places.
  2. State an equation that is satisfied by \(\alpha\) and hence find the exact value of \(\alpha\).

(i)
AnswerMarks Guidance
Use the iterative formula correctly at least onceM1
Obtain final answer 2.29A1
Show sufficient iterations to justify its accuracy to 2 d.p. (must be working to 4 d.p.) – 3 iterations are sufficientB1 [3]
(ii)
AnswerMarks Guidance
State equation \(x = \frac{2}{3}x + \frac{4}{x^2}\), or equivalentB1
Derive the exact answer \(\alpha\) (or \(x\)) \(= \sqrt{12}\), or equivalentB1 [2]
**(i)**

Use the iterative formula correctly at least once | M1 |
Obtain final answer 2.29 | A1 |
Show sufficient iterations to justify its accuracy to 2 d.p. (must be working to 4 d.p.) – 3 iterations are sufficient | B1 | [3]

**(ii)**

State equation $x = \frac{2}{3}x + \frac{4}{x^2}$, or equivalent | B1 |
Derive the exact answer $\alpha$ (or $x$) $= \sqrt{12}$, or equivalent | B1 | [2]
2 The sequence of values given by the iterative formula

$$x _ { n + 1 } = \frac { 2 x _ { n } } { 3 } + \frac { 4 } { x _ { n } ^ { 2 } }$$

with initial value $x _ { 1 } = 2$, converges to $\alpha$.\\
(i) Use this iterative formula to determine $\alpha$ correct to 2 decimal places, giving the result of each iteration to 4 decimal places.\\
(ii) State an equation that is satisfied by $\alpha$ and hence find the exact value of $\alpha$.

\hfill \mbox{\textit{CAIE P2 2007 Q2 [5]}}