Edexcel C1 — Question 6 10 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeProve sum formula
DifficultyModerate -0.8 Part (a) is a standard proof of the arithmetic series formula that appears in most textbooks and requires only algebraic manipulation of a well-known result. Parts (b) and (c) are routine applications of the formula with straightforward substitution and arithmetic. This is a typical C1-level question testing basic recall and application rather than problem-solving or insight.
Spec1.01a Proof: structure of mathematical proof and logical steps1.04h Arithmetic sequences: nth term and sum formulae1.04k Modelling with sequences: compound interest, growth/decay

6. (a) An arithmetic series has first term \(a\) and common difference \(d\). Prove that the sum of the first \(n\) terms of the series is \(\frac { 1 } { 2 } n [ 2 a + ( n - 1 ) d ]\). A company made a profit of \(\pounds 54000\) in the year 2001. A model for future performance assumes that yearly profits will increase in an arithmetic sequence with common difference \(\pounds d\). This model predicts total profits of \(\pounds 619200\) for the 9 years 2001 to 2009 inclusive.
(b) Find the value of \(d\). Using your value of \(d\),
(c) find the predicted profit for the year 2011.

Question 6:
Part (a)
AnswerMarks Guidance
\(S = a + (a+d) + (a+2d) + \ldots + [a+(n-1)d]\)B1
\(S = [a+(n-1)d] + [a+(n-2)d] + \ldots + a\)M1
Add: \(2S = n[2a + (n-1)d] \Rightarrow S = \frac{1}{2}n[2a+(n-1)d]\)M1 A1 (4 marks)
Part (b)
AnswerMarks Guidance
\(a = 54000\) and \(n = 9\)B1
\(619200 = \frac{1}{2} \times 9 \times (2 \times 54000 + 8d)\)M1 A1ft
\(d = 3700\)A1 (4 marks)
Part (c)
AnswerMarks Guidance
\(a + (n-1)d = a + 10d = 54000 + 10d = £91000\)M1 A1 (2 marks) (8 marks)
## Question 6:

### Part (a)
$S = a + (a+d) + (a+2d) + \ldots + [a+(n-1)d]$ | B1 |

$S = [a+(n-1)d] + [a+(n-2)d] + \ldots + a$ | M1 |

Add: $2S = n[2a + (n-1)d] \Rightarrow S = \frac{1}{2}n[2a+(n-1)d]$ | M1 A1 | (4 marks)

### Part (b)
$a = 54000$ and $n = 9$ | B1 |

$619200 = \frac{1}{2} \times 9 \times (2 \times 54000 + 8d)$ | M1 A1ft |

$d = 3700$ | A1 | (4 marks)

### Part (c)
$a + (n-1)d = a + 10d = 54000 + 10d = £91000$ | M1 A1 | (2 marks) **(8 marks)**

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6. (a) An arithmetic series has first term $a$ and common difference $d$. Prove that the sum of the first $n$ terms of the series is $\frac { 1 } { 2 } n [ 2 a + ( n - 1 ) d ]$.

A company made a profit of $\pounds 54000$ in the year 2001. A model for future performance assumes that yearly profits will increase in an arithmetic sequence with common difference $\pounds d$. This model predicts total profits of $\pounds 619200$ for the 9 years 2001 to 2009 inclusive.\\
(b) Find the value of $d$.

Using your value of $d$,\\
(c) find the predicted profit for the year 2011.\\

\hfill \mbox{\textit{Edexcel C1  Q6 [10]}}