AQA C1 2005 January — Question 7 10 marks

Exam BoardAQA
ModuleC1 (Core Mathematics 1)
Year2005
SessionJanuary
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscriminant and conditions for roots
TypeShow discriminant inequality, then solve
DifficultyStandard +0.3 This is a standard discriminant question with algebraic manipulation. Part (a) is routine simplification, part (b)(i) requires setting b²-4ac≥0 and factorizing (guided by 'show that'), and part (b)(ii) involves solving a quadratic inequality—all well-practiced C1 techniques with no novel insight required. Slightly above average due to the multi-step algebra and inequality solving.
Spec1.02d Quadratic functions: graphs and discriminant conditions

7
  1. Simplify \(( k + 5 ) ^ { 2 } - 12 k ( k + 2 )\).
  2. The quadratic equation \(3 ( k + 2 ) x ^ { 2 } + ( k + 5 ) x + k = 0\) has real roots.
    1. Show that \(( k - 1 ) ( 11 k + 25 ) \leqslant 0\).
    2. Hence find the possible values of \(k\).

AnswerMarks
Total: 10
TOTAL: 75
| | **Total: 10**

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# TOTAL: 75
7
\begin{enumerate}[label=(\alph*)]
\item Simplify $( k + 5 ) ^ { 2 } - 12 k ( k + 2 )$.
\item The quadratic equation $3 ( k + 2 ) x ^ { 2 } + ( k + 5 ) x + k = 0$ has real roots.
\begin{enumerate}[label=(\roman*)]
\item Show that $( k - 1 ) ( 11 k + 25 ) \leqslant 0$.
\item Hence find the possible values of $k$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA C1 2005 Q7 [10]}}