Edexcel D1 2009 January — Question 2 8 marks

Exam BoardEdexcel
ModuleD1 (Decision Mathematics 1)
Year2009
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMinimum Spanning Trees
TypeApply Kruskal's algorithm
DifficultyEasy -1.3 This is a straightforward application of Kruskal's algorithm to a small 6-vertex network with clearly tabulated edge weights. The algorithm is mechanical (sort edges, add if no cycle), requires no problem-solving insight, and is a standard textbook exercise testing only procedural recall of the algorithm.
Spec7.04c Travelling salesman upper bound: nearest neighbour method

2.
\(\mathbf { A }\)\(\mathbf { B }\)\(\mathbf { C }\)\(\mathbf { D }\)\(\mathbf { E }\)\(\mathbf { F }\)
\(\mathbf { A }\)-24--2322
\(\mathbf { B }\)24-18191720
\(\mathbf { C }\)-18-1114-
\(\mathbf { D }\)-1911-13-
\(\mathbf { E }\)23171413-21
\(\mathbf { F }\)2220--21-
The table shows the distances, in metres, between six vertices, \(\mathbf { A } , \mathbf { B } , \mathbf { C } , \mathbf { D } , \mathbf { E }\) and \(\mathbf { F }\), in a network.
  1. Draw the weighted network using the vertices given in Diagram 1 in the answer booklet.
  2. Use Kruskal's algorithm to find a minimum spanning tree. You should list the edges in the order that you consider them and state whether you are adding them to your minimum spanning tree.
  3. Draw your tree on Diagram 2 in the answer booklet and find its total weight.

Question 2:
Part (a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Network drawn with correct structureM1 More than 10 arcs
All arcs correctA1 All arcs correct
All values correct (AF=22, AB=24, AE=23, BF=20, BE=17, BF=19, CE=18, CF=14, CD=11, DE=13, DF=21)A1 All values correct
Part (b)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
CD, DE, reject CE, BE, reject BC, reject BD, BF, reject EF, AFM1 A1 First three arcs correctly chosen; All used arcs selected correctly
11, 13, 14, 17, 18, 19, 20, 21, 22A1 All rejected arcs selected in correct order
Minimum spanning tree diagram showing CD, DE, BE, BF, AFB1 CAO for arcs – numbers not needed. NO ft
Weight of tree \(= 83\) (m)B1 CAO 83, condone units
# Question 2:

## Part (a)
| Answer/Working | Marks | Guidance |
|---|---|---|
| Network drawn with correct structure | M1 | More than 10 arcs |
| All arcs correct | A1 | All arcs correct |
| All values correct (AF=22, AB=24, AE=23, BF=20, BE=17, BF=19, CE=18, CF=14, CD=11, DE=13, DF=21) | A1 | All values correct |

## Part (b)
| Answer/Working | Marks | Guidance |
|---|---|---|
| CD, DE, reject CE, BE, reject BC, reject BD, BF, reject EF, AF | M1 A1 | First three arcs correctly chosen; All used arcs selected correctly |
| 11, 13, 14, 17, 18, 19, 20, 21, 22 | A1 | All rejected arcs selected in correct order |
| Minimum spanning tree diagram showing CD, DE, BE, BF, AF | B1 | CAO for arcs – numbers not needed. NO ft |
| Weight of tree $= 83$ (m) | B1 | CAO 83, condone units |

---
2.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | c | }
\hline
 & $\mathbf { A }$ & $\mathbf { B }$ & $\mathbf { C }$ & $\mathbf { D }$ & $\mathbf { E }$ & $\mathbf { F }$ \\
\hline
$\mathbf { A }$ & - & 24 & - & - & 23 & 22 \\
\hline
$\mathbf { B }$ & 24 & - & 18 & 19 & 17 & 20 \\
\hline
$\mathbf { C }$ & - & 18 & - & 11 & 14 & - \\
\hline
$\mathbf { D }$ & - & 19 & 11 & - & 13 & - \\
\hline
$\mathbf { E }$ & 23 & 17 & 14 & 13 & - & 21 \\
\hline
$\mathbf { F }$ & 22 & 20 & - & - & 21 & - \\
\hline
\end{tabular}
\end{center}

The table shows the distances, in metres, between six vertices, $\mathbf { A } , \mathbf { B } , \mathbf { C } , \mathbf { D } , \mathbf { E }$ and $\mathbf { F }$, in a network.
\begin{enumerate}[label=(\alph*)]
\item Draw the weighted network using the vertices given in Diagram 1 in the answer booklet.
\item Use Kruskal's algorithm to find a minimum spanning tree. You should list the edges in the order that you consider them and state whether you are adding them to your minimum spanning tree.
\item Draw your tree on Diagram 2 in the answer booklet and find its total weight.
\end{enumerate}

\hfill \mbox{\textit{Edexcel D1 2009 Q2 [8]}}