CAIE P1 2022 November — Question 5 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2022
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFunction Transformations
TypeComposite transformation sketch
DifficultyModerate -0.8 This is a straightforward application of standard transformation rules: a horizontal stretch followed by a vertical translation. Part (a) requires sketching transformed key points, and part (b) requires writing g(x) = f(2x) + 1, both routine procedures covered extensively in P1 with no problem-solving or novel insight required.
Spec1.02w Graph transformations: simple transformations of f(x)1.02x Combinations of transformations: multiple transformations

5 The graph with equation \(y = \mathrm { f } ( x )\) is transformed to the graph with equation \(y = \mathrm { g } ( x )\) by a stretch in the \(x\)-direction with factor 0.5 , followed by a translation of \(\binom { 0 } { 1 }\).
  1. The diagram below shows the graph of \(y = \mathrm { f } ( x )\). On the diagram sketch the graph of \(y = \mathrm { g } ( x )\). \includegraphics[max width=\textwidth, alt={}, center]{5d26c357-ea9f-47d9-8eca-2152901cf2f1-07_613_1527_623_342}
  2. Find an expression for \(\mathrm { g } ( x )\) in terms of \(\mathrm { f } ( x )\).

Question 5(a):
AnswerMarks Guidance
AnswerMark Guidance
Three points at the bottom of their transformed graph plotted at \(y = 2\)B1 All 5 points of the graph must be connected.
Bottom three points of \(\mathsf{M}\) at \(x = 0,\ x = 1\) & \(x = 2\)B1 Must be this shape.
All correctB1 Condone extra cycles outside \(0 \leqslant x \leqslant 2\). SC: If B0 B0 scored, B1 available for \(\Lambda\) in one of correct positions or all 5 points correctly plotted and not connected or correctly sized shape in the wrong position.
Question 5(b):
AnswerMarks Guidance
AnswerMark Guidance
\([g(x) =]\ f(2x) + 1\)B1 B1 Award marks for their final answer: \(f(2x)\) B1, \(+ 1\) B1. Condone \(y =\) or \(f(x) =\).
## Question 5(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| Three points at the bottom of their transformed graph plotted at $y = 2$ | B1 | All 5 points of the graph must be connected. |
| Bottom three points of $\mathsf{M}$ at $x = 0,\ x = 1$ & $x = 2$ | B1 | Must be this shape. |
| All correct | B1 | Condone extra cycles outside $0 \leqslant x \leqslant 2$. **SC:** If B0 B0 scored, B1 available for $\Lambda$ in one of correct positions **or** all 5 points correctly plotted and not connected **or** correctly sized shape in the wrong position. |

## Question 5(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| $[g(x) =]\ f(2x) + 1$ | B1 B1 | Award marks for their final answer: $f(2x)$ B1, $+ 1$ B1. Condone $y =$ or $f(x) =$. |

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5 The graph with equation $y = \mathrm { f } ( x )$ is transformed to the graph with equation $y = \mathrm { g } ( x )$ by a stretch in the $x$-direction with factor 0.5 , followed by a translation of $\binom { 0 } { 1 }$.
\begin{enumerate}[label=(\alph*)]
\item The diagram below shows the graph of $y = \mathrm { f } ( x )$.

On the diagram sketch the graph of $y = \mathrm { g } ( x )$.\\
\includegraphics[max width=\textwidth, alt={}, center]{5d26c357-ea9f-47d9-8eca-2152901cf2f1-07_613_1527_623_342}
\item Find an expression for $\mathrm { g } ( x )$ in terms of $\mathrm { f } ( x )$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2022 Q5 [5]}}