Edexcel S1 2004 November — Question 5 7 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Year2004
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPrinciple of Inclusion/Exclusion
TypeBasic Inclusion-Exclusion with Two Sets
DifficultyEasy -1.3 This is a straightforward S1 question requiring direct application of the inclusion-exclusion formula P(A∪B) = P(A) + P(B) - P(A∩B) and basic Venn diagram manipulation. All values are given, requiring only substitution and simple arithmetic with no problem-solving or conceptual insight needed.
Spec2.03a Mutually exclusive and independent events2.03b Probability diagrams: tree, Venn, sample space

5. The events \(A\) and \(B\) are such that \(\mathrm { P } ( A ) = \frac { 1 } { 2 } , \mathrm { P } ( B ) = \frac { 1 } { 3 }\) and \(\mathrm { P } ( A \cap B ) = \frac { 1 } { 4 }\).
  1. Using the space below, represent these probabilities in a Venn diagram. Hence, or otherwise, find
  2. \(\mathrm { P } ( A \cup B )\),
  3. \(\mathrm { P } \left( \begin{array} { l l } A & B ^ { \prime } \end{array} \right)\)

Question 5:
Part (a):
AnswerMarks Guidance
WorkingMark Guidance
2 intersecting closed curves in a boxM1
Both \(\frac{1}{4}\), \(\frac{1}{12}\) placed correctlyB1, B1
\(\frac{5}{12}\) placed correctlyB1\(\int\)
Part (b):
AnswerMarks Guidance
WorkingMark Guidance
\(P(A \cup B) = \frac{7}{12}\)B1\(\int\) 0.583 or \(0.58\dot{3}\) or \(\frac{7}{12}\)
Part (c):
AnswerMarks Guidance
WorkingMark Guidance
\(P(AB') = \frac{P(A \cap B')}{P(B')} = \frac{\frac{1}{4}}{\frac{2}{3}} = \frac{3}{8}\) or 0.375 M1, A1
## Question 5:

### Part (a):
| Working | Mark | Guidance |
|---------|------|----------|
| 2 intersecting closed curves in a box | M1 | |
| Both $\frac{1}{4}$, $\frac{1}{12}$ placed correctly | B1, B1 | |
| $\frac{5}{12}$ placed correctly | B1$\int$ | |

### Part (b):
| Working | Mark | Guidance |
|---------|------|----------|
| $P(A \cup B) = \frac{7}{12}$ | B1$\int$ | 0.583 or $0.58\dot{3}$ or $\frac{7}{12}$ |

### Part (c):
| Working | Mark | Guidance |
|---------|------|----------|
| $P(A|B') = \frac{P(A \cap B')}{P(B')} = \frac{\frac{1}{4}}{\frac{2}{3}} = \frac{3}{8}$ or 0.375 | M1, A1 | their fractions divided, cao |

---
5. The events $A$ and $B$ are such that $\mathrm { P } ( A ) = \frac { 1 } { 2 } , \mathrm { P } ( B ) = \frac { 1 } { 3 }$ and $\mathrm { P } ( A \cap B ) = \frac { 1 } { 4 }$.
\begin{enumerate}[label=(\alph*)]
\item Using the space below, represent these probabilities in a Venn diagram.

Hence, or otherwise, find
\item $\mathrm { P } ( A \cup B )$,
\item $\mathrm { P } \left( \begin{array} { l l } A & B ^ { \prime } \end{array} \right)$
\end{enumerate}

\hfill \mbox{\textit{Edexcel S1 2004 Q5 [7]}}