Edexcel S1 2018 June — Question 7 12 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Year2018
SessionJune
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConditional Probability
TypeGiven conditional, find joint or marginal
DifficultyStandard +0.3 This is a standard S1 conditional probability question requiring systematic application of probability rules (conditional probability formula, De Morgan's laws, independence, mutual exclusivity) across multiple parts. While it has several steps and requires careful bookkeeping, each individual technique is routine for A-level statistics, making it slightly easier than average overall.
Spec2.03a Mutually exclusive and independent events2.03b Probability diagrams: tree, Venn, sample space2.03c Conditional probability: using diagrams/tables2.03d Calculate conditional probability: from first principles

  1. Events \(A\) and \(B\) are such that
$$\mathrm { P } ( A ) = 0.5 \quad \mathrm { P } ( A \mid B ) = \frac { 2 } { 3 } \quad \mathrm { P } \left( A ^ { \prime } \cup B ^ { \prime } \right) = 0.6$$
  1. Find \(\mathrm { P } ( B )\)
  2. Find \(\mathrm { P } \left( A ^ { \prime } \mid B ^ { \prime } \right)\) The event \(C\) has \(\mathrm { P } ( C ) = 0.15\) The events \(A\) and \(C\) are mutually exclusive. The events \(B\) and \(C\) are independent.
  3. Find \(\mathrm { P } ( B \cap C )\)
  4. Draw a Venn diagram to illustrate the events \(A , B\) and \(C\) and the probabilities for each region.

Question 7:
Part (a):
AnswerMarks Guidance
AnswerMarks Guidance
\(P(A\cap B)=0.4\)B1
\(P(A\mid B)=\dfrac{0.4}{P(B)}=\dfrac{2}{3}\)M1 \(\frac{\text{their }0.4}{P(B)}=\frac{2}{3}\); use of \(P(A\cap B)=P(A)\times P(B)\) is M0
\(P(B)=0.6\)A1
Part (b):
AnswerMarks Guidance
AnswerMarks Guidance
\(P(A'\mid B')=\dfrac{0.5+\text{'0.4'}-\text{'0.6'}}{1-\text{'0.6'}}=\dfrac{3}{4}\)M1 A1 M1 for \(\frac{0.5+\text{their }P(A\cap B)-\text{their (a)}}{1-\text{their (a)}}\)
Part (c):
AnswerMarks Guidance
AnswerMarks Guidance
\(P(B\cap C)=\text{'0.6'}\times0.15=0.09\)M1 A1 M1 their (a) \(\times0.15\), \(0<\) their (a) \(<1\)
Part (d):
AnswerMarks Guidance
AnswerMarks Guidance
3 circles labelled A, B, C with B intersecting A and C, and \(P(A\cap C)=0\)M1 Do not allow blanks as 0s
0.09 and 0.06 or their (c) and \(0.15-\) their (c)M1
0.4 and 0.1 or probabilities in A such that \(P(A)=0.5\)M1
0.11 and 0.24 or all 6 probs add to 1 and probs in B such that \(P(B)=\text{'0.6'}\)A1ft dep on 1st M1
All correct with box: 0.1, 0.4, 0.11, 0.09, 0.06, 0.24A1 NOTE: No labels allow access to 2nd and 3rd M1 marks ONLY
The image appears to be essentially blank/empty, containing only the Pearson Education Limited copyright notice at the bottom and "PMT" in the top right corner. There is no mark scheme content visible on this page to extract.
This appears to be a back cover or blank page from a Pearson mark scheme document. Could you share the pages that actually contain the mark scheme questions and answers?
# Question 7:

## Part (a):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $P(A\cap B)=0.4$ | B1 | |
| $P(A\mid B)=\dfrac{0.4}{P(B)}=\dfrac{2}{3}$ | M1 | $\frac{\text{their }0.4}{P(B)}=\frac{2}{3}$; use of $P(A\cap B)=P(A)\times P(B)$ is M0 |
| $P(B)=0.6$ | A1 | |

## Part (b):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $P(A'\mid B')=\dfrac{0.5+\text{'0.4'}-\text{'0.6'}}{1-\text{'0.6'}}=\dfrac{3}{4}$ | M1 A1 | M1 for $\frac{0.5+\text{their }P(A\cap B)-\text{their (a)}}{1-\text{their (a)}}$ |

## Part (c):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $P(B\cap C)=\text{'0.6'}\times0.15=0.09$ | M1 A1 | M1 their (a) $\times0.15$, $0<$ their (a) $<1$ |

## Part (d):
| Answer | Marks | Guidance |
|--------|-------|----------|
| 3 circles labelled A, B, C with B intersecting A and C, and $P(A\cap C)=0$ | M1 | Do not allow blanks as 0s |
| 0.09 and 0.06 or their (c) and $0.15-$ their (c) | M1 | |
| 0.4 and 0.1 or probabilities in A such that $P(A)=0.5$ | M1 | |
| 0.11 and 0.24 or all 6 probs add to 1 and probs in B such that $P(B)=\text{'0.6'}$ | A1ft | dep on 1st M1 |
| All correct with box: 0.1, 0.4, 0.11, 0.09, 0.06, 0.24 | A1 | NOTE: No labels allow access to 2nd and 3rd M1 marks ONLY |

The image appears to be essentially blank/empty, containing only the Pearson Education Limited copyright notice at the bottom and "PMT" in the top right corner. There is no mark scheme content visible on this page to extract.

This appears to be a back cover or blank page from a Pearson mark scheme document. Could you share the pages that actually contain the mark scheme questions and answers?
\begin{enumerate}
  \item Events $A$ and $B$ are such that
\end{enumerate}

$$\mathrm { P } ( A ) = 0.5 \quad \mathrm { P } ( A \mid B ) = \frac { 2 } { 3 } \quad \mathrm { P } \left( A ^ { \prime } \cup B ^ { \prime } \right) = 0.6$$

(a) Find $\mathrm { P } ( B )$\\
(b) Find $\mathrm { P } \left( A ^ { \prime } \mid B ^ { \prime } \right)$

The event $C$ has $\mathrm { P } ( C ) = 0.15$

The events $A$ and $C$ are mutually exclusive.

The events $B$ and $C$ are independent.\\
(c) Find $\mathrm { P } ( B \cap C )$\\
(d) Draw a Venn diagram to illustrate the events $A , B$ and $C$ and the probabilities for each region.\\

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\hfill \mbox{\textit{Edexcel S1 2018 Q7 [12]}}