A-Level Maths
Courses
Papers
Questions
Search
Courses
UFM Additional Further Pure
Number Theory
Q3
OCR Further Additional Pure 2019 June — Question 3
Exam Board
OCR
Module
Further Additional Pure (Further Additional Pure)
Year
2019
Session
June
Topic
Number Theory
3
Solve \(7 x \equiv 6 ( \bmod 19 )\).
Show that the following simultaneous linear congruences have no solution. $$x \equiv 3 ( \bmod 4 ) , x \equiv 4 ( \bmod 6 )$$
This paper
(8 questions)
View full paper
Q1
Q2
Q3
Q4
Q5
Q6
Q7
Q8