OCR Further Statistics 2023 June — Question 4 10 marks

Exam BoardOCR
ModuleFurther Statistics (Further Statistics)
Year2023
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHypothesis test of Spearman’s rank correlation coefficien
TypeHypothesis test for positive correlation
DifficultyStandard +0.3 This is a straightforward application of Spearman's rank correlation coefficient with a small sample (n=5), making calculations simple. The question guides students through standard steps (justification, calculation, hypothesis test) with no conceptual surprises. The ranking is trivial since Magazine II data is already monotonic, and part (d) simply requires reversing ranks. Slightly above average difficulty only because it's Further Maths content, but mechanically routine.
Spec5.08f Hypothesis test: Spearman rank5.08g Compare: Pearson vs Spearman

4 Two magazines give numerical ratings to hi-fi systems. Li wishes to test whether there is agreement between the opinions of the magazines. Li chooses a random sample of 5 hi -fi systems and looks up the ratings given by the two magazines. The results are shown in the table.
SystemABCDE
Magazine I6875778392
Magazine II3025403545
  1. Give a reason why Li might choose to use a test based on Spearman's rank correlation coefficient rather than on Pearson's product-moment correlation coefficient.
  2. Calculate the value of Spearman's rank correlation coefficient for the data.
  3. Use your answer to part (b) to carry out a hypothesis test at the \(5 \%\) significance level.
  4. The value of Spearman's rank correlation coefficient between the ratings given by magazine I and by a third magazine, magazine III, has the same numerical value as the answer to part (b) but with the sign changed. In the Printed Answer Booklet, complete the table showing the rankings given by magazine III.

Question 4:
AnswerMarks Guidance
4(a) E.g. ratings are arbitrary, or population not bivariate
normal, or r measures only linear correlationB1
[1]2.4 Not “data are ratings not scores” unless explained further. Not “population
may not be normal”, nor just “looking for agreement not correlation”
AnswerMarks
(b)I 5 4 3 2 1
II 4 5 2 3 1
d2 = 4
6d2
r = 1− = 0.8
s
AnswerMarks
5(52−1)B1
B1
M1
A1
AnswerMarks
[4]1.1
1.1
1.2
AnswerMarks
1.1Or with rankings reversed (2 1 4 3 5)
4 stated or implied
Correct formula used, with reasonable attempt at d2 using rankings
0.8 or 4/5 only
AnswerMarks
(c)H :  = 0, H :  > 0, where  is the population rank
0 s 1 s s
correlation coefficient between the rankings given by
the two magazines, or H : no correlation between
0
population rankings, H : positive correlation
1
0.8 < 0.9 so do not reject H .
0
Insufficient evidence of agreement between
AnswerMarks
magazines’ opinions.B2
B1ft
B1ft
AnswerMarks
[4]1.1
2.5
1.1
AnswerMarks
2.2bOne error, e.g. two-tailed or  not defined, or verbal: B1
s
If verbal, must include clearly one-sided H for B2
1
Allow B1 for H :  = 0, H :  > 0. Same marks also for using r or r
0 1 s
For B2 must include either context or “population” (or both).
Allow any of correlation, association, agreement.
Compare with 0.9 and do not reject, FT on their r if M1 gained in (b).
s
FT on CV 1.0 if hypotheses two-tailed. Allow “Accept H ”, etc
1
Contextualised, not too assertive, FT as above. Not “evidence of no
agreement”, but allow from CV 1.0. Needs hypotheses right way round
AnswerMarks Guidance
(d)Magazine III 2 1 4 3 5 B1ft
[1]3.1b Reverse of rankings of II used in part (b) (= 6 – their rankings of II)
NB: “4 5 2 3 1” could come from ranking high-to-low.
AnswerMarks Guidance
I5 4
II4 5
Magazine III2 1
ATakes into account magnitudes of scores (wrong) B0
BTakes into account differences in ranks (wrong) B0
CNot enough data to use PMCC B0
DOne magazine may have a stricter standard and Spearman would eliminate this (scaling would not affect PMCC) B0
ESpearman’s Rank will not be as much affected by uncertainties in measurements/anomalous results (too vague?) B0
FEliminates the magnitude of the scores (too vague) B0
GTesting association rather than a linear relationship (generally allow any answer that says SRCC doesn’t need linearity) B1
HLooking for agreement between opinions rather than between numerical values, so association not correlation B1
IThe numbers are just opinions B1
JH : no correlation between magazine’s ratings, H : positive correlation
0 1B2
KH : no correlation,  = 0, H : positive correlation,  > 0 (neither the verbal nor the symbolic statement scores B2)
0 s 1 sB1
LH : r = 0, H : r > 0, where r is the correlation coefficient between the rankings given by the magazines
0 1B2
MH : no agreement between population rankings, H : there is agreement (2-tailed so B1B0)
0 1
0.8 < 1.0 so do not reject H . (FT on 2-tailed)
0
AnswerMarks
Insufficient evidence of no agreement between magazines’ opinions. (FT)B1B0
B1
B1
AnswerMarks
NH : no positive agreement between population rankings, H : positive agreement (1-tailed so B1B1 – allow this H )
0 1 0
0.8 < 1.0 so do not reject H . (NO FT on 1-tailed if 0.9 not used)
0
AnswerMarks
Insufficient evidence of no agreement between magazines’ opinions. (NO FT)B1B1
B0
B0
AnswerMarks
OH : no agreement between population rankings, H : there is agreement (2-tailed so B1B0)
0 1
0.8 < 0.9 so do not reject H . (allow, even though inconsistent)
0
Significance evidence of agreement between magazines’ opinions. (can’t assert that H is correct)
AnswerMarks
0B1B0
B1
B0
Question 4:
4 | (a) | E.g. ratings are arbitrary, or population not bivariate
normal, or r measures only linear correlation | B1
[1] | 2.4 | Not “data are ratings not scores” unless explained further. Not “population
may not be normal”, nor just “looking for agreement not correlation”
(b) | I 5 4 3 2 1
II 4 5 2 3 1
d2 = 4
6d2
r = 1− = 0.8
s
5(52−1) | B1
B1
M1
A1
[4] | 1.1
1.1
1.2
1.1 | Or with rankings reversed (2 1 4 3 5)
4 stated or implied
Correct formula used, with reasonable attempt at d2 using rankings
0.8 or 4/5 only
(c) | H :  = 0, H :  > 0, where  is the population rank
0 s 1 s s
correlation coefficient between the rankings given by
the two magazines, or H : no correlation between
0
population rankings, H : positive correlation
1
0.8 < 0.9 so do not reject H .
0
Insufficient evidence of agreement between
magazines’ opinions. | B2
B1ft
B1ft
[4] | 1.1
2.5
1.1
2.2b | One error, e.g. two-tailed or  not defined, or verbal: B1
s
If verbal, must include clearly one-sided H for B2
1
Allow B1 for H :  = 0, H :  > 0. Same marks also for using r or r
0 1 s
For B2 must include either context or “population” (or both).
Allow any of correlation, association, agreement.
Compare with 0.9 and do not reject, FT on their r if M1 gained in (b).
s
FT on CV 1.0 if hypotheses two-tailed. Allow “Accept H ”, etc
1
Contextualised, not too assertive, FT as above. Not “evidence of no
agreement”, but allow from CV 1.0. Needs hypotheses right way round
(d) | Magazine III 2 1 4 3 5 | B1ft
[1] | 3.1b | Reverse of rankings of II used in part (b) (= 6 – their rankings of II)
NB: “4 5 2 3 1” could come from ranking high-to-low.
I | 5 | 4 | 3 | 2 | 1
II | 4 | 5 | 2 | 3 | 1
Magazine III | 2 | 1 | 4 | 3 | 5
A | Takes into account magnitudes of scores (wrong) | B0
B | Takes into account differences in ranks (wrong) | B0
C | Not enough data to use PMCC | B0
D | One magazine may have a stricter standard and Spearman would eliminate this (scaling would not affect PMCC) | B0
E | Spearman’s Rank will not be as much affected by uncertainties in measurements/anomalous results (too vague?) | B0
F | Eliminates the magnitude of the scores (too vague) | B0
G | Testing association rather than a linear relationship (generally allow any answer that says SRCC doesn’t need linearity) | B1
H | Looking for agreement between opinions rather than between numerical values, so association not correlation | B1
I | The numbers are just opinions | B1
J | H : no correlation between magazine’s ratings, H : positive correlation
0 1 | B2
K | H : no correlation,  = 0, H : positive correlation,  > 0 (neither the verbal nor the symbolic statement scores B2)
0 s 1 s | B1
L | H : r = 0, H : r > 0, where r is the correlation coefficient between the rankings given by the magazines
0 1 | B2
M | H : no agreement between population rankings, H : there is agreement (2-tailed so B1B0)
0 1
0.8 < 1.0 so do not reject H . (FT on 2-tailed)
0
Insufficient evidence of no agreement between magazines’ opinions. (FT) | B1B0
B1
B1
N | H : no positive agreement between population rankings, H : positive agreement (1-tailed so B1B1 – allow this H )
0 1 0
0.8 < 1.0 so do not reject H . (NO FT on 1-tailed if 0.9 not used)
0
Insufficient evidence of no agreement between magazines’ opinions. (NO FT) | B1B1
B0
B0
O | H : no agreement between population rankings, H : there is agreement (2-tailed so B1B0)
0 1
0.8 < 0.9 so do not reject H . (allow, even though inconsistent)
0
Significance evidence of agreement between magazines’ opinions. (can’t assert that H is correct)
0 | B1B0
B1
B0
4 Two magazines give numerical ratings to hi-fi systems. Li wishes to test whether there is agreement between the opinions of the magazines. Li chooses a random sample of 5 hi -fi systems and looks up the ratings given by the two magazines. The results are shown in the table.

\begin{center}
\begin{tabular}{ | l | c | c | c | c | c | }
\hline
System & A & B & C & D & E \\
\hline
Magazine I & 68 & 75 & 77 & 83 & 92 \\
\hline
Magazine II & 30 & 25 & 40 & 35 & 45 \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\alph*)]
\item Give a reason why Li might choose to use a test based on Spearman's rank correlation coefficient rather than on Pearson's product-moment correlation coefficient.
\item Calculate the value of Spearman's rank correlation coefficient for the data.
\item Use your answer to part (b) to carry out a hypothesis test at the $5 \%$ significance level.
\item The value of Spearman's rank correlation coefficient between the ratings given by magazine I and by a third magazine, magazine III, has the same numerical value as the answer to part (b) but with the sign changed.

In the Printed Answer Booklet, complete the table showing the rankings given by magazine III.
\end{enumerate}

\hfill \mbox{\textit{OCR Further Statistics 2023 Q4 [10]}}