OCR Further Mechanics AS 2020 November — Question 1 5 marks

Exam BoardOCR
ModuleFurther Mechanics AS (Further Mechanics AS)
Year2020
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPower and driving force
TypeFind steady/maximum speed given power
DifficultyModerate -0.8 This is a straightforward application of the power-force-velocity relationship (P=Fv) and Newton's second law. Part (a) requires simple rearrangement of P=Fv at constant speed where driving force equals resistance. Part (b) uses F=ma after finding the driving force from power. Both parts are standard textbook exercises with direct formula application and minimal problem-solving required.
Spec6.02k Power: rate of doing work6.02l Power and velocity: P = Fv

1 A car of mass 1200 kg is driven on a long straight horizontal road. There is a constant force of 250 N resisting the motion of the car. The engine of the car is working at a constant power of 10 kW .
  1. The car can travel at constant speed \(v \mathrm {~ms} ^ { - 1 }\) along the road. Find \(v\).
  2. Find the acceleration of the car at an instant when its speed is \(30 \mathrm {~ms} ^ { - 1 }\).

Question 1:
Part (a)
AnswerMarks Guidance
AnswerMarks Guidance
At constant velocity, \(F = 250 = 10000/v\)M1 Tractive force \(= P/v =\) resistance
\(v = 40\)A1
Part (b)
AnswerMarks Guidance
AnswerMarks Guidance
\(n = \frac{10000}{30}\)M1 Use of \(P = Dv\) where \(D\) is tractive force
\(\frac{10000}{30} - 250 = 1200a\)M1 Attempt NII with 2 forces (one of which could be just "\(D\)")
awrt \(0.069\) ms\(^{-2}\)A1
## Question 1:

### Part (a)
| Answer | Marks | Guidance |
|--------|-------|----------|
| At constant velocity, $F = 250 = 10000/v$ | M1 | Tractive force $= P/v =$ resistance |
| $v = 40$ | A1 | |

### Part (b)
| Answer | Marks | Guidance |
|--------|-------|----------|
| $n = \frac{10000}{30}$ | M1 | Use of $P = Dv$ where $D$ is tractive force |
| $\frac{10000}{30} - 250 = 1200a$ | M1 | Attempt NII with 2 forces (one of which could be just "$D$") |
| awrt $0.069$ ms$^{-2}$ | A1 | |

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1 A car of mass 1200 kg is driven on a long straight horizontal road. There is a constant force of 250 N resisting the motion of the car. The engine of the car is working at a constant power of 10 kW .
\begin{enumerate}[label=(\alph*)]
\item The car can travel at constant speed $v \mathrm {~ms} ^ { - 1 }$ along the road. Find $v$.
\item Find the acceleration of the car at an instant when its speed is $30 \mathrm {~ms} ^ { - 1 }$.
\end{enumerate}

\hfill \mbox{\textit{OCR Further Mechanics AS 2020 Q1 [5]}}