OCR Further Statistics AS 2021 November — Question 3 7 marks

Exam BoardOCR
ModuleFurther Statistics AS (Further Statistics AS)
Year2021
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear regression
TypeExplain least squares concept
DifficultyModerate -0.3 This is a straightforward Further Statistics question testing standard regression concepts: explaining least squares (bookwork), calculating a regression line from summary statistics using standard formulae, and applying simple linear transformations. While it's Further Maths content, these are routine computational exercises with no problem-solving insight required, making it slightly easier than an average A-level question overall.
Spec5.09a Dependent/independent variables5.09b Least squares regression: concepts5.09c Calculate regression line5.09d Linear coding: effect on regression

3
  1. Using the scatter diagram in the Printed Answer Booklet, explain what is meant by least squares in the context of a regression line of \(y\) on \(x\).
  2. A set of bivariate data \(( t , u )\) is summarised as follows. \(n = 5 \quad \sum t = 35 \quad \sum u = 54\) \(\sum t ^ { 2 } = 285 \quad \sum u ^ { 2 } = 758 \quad \sum \mathrm { tu } = 460\)
    1. Calculate the equation of the regression line of \(u\) on \(t\).
    2. The variables \(t\) and \(u\) are now scaled using the following scaling. \(\mathrm { v } = 2 \mathrm { t } , \mathrm { w } = \mathrm { u } + 4\) Find the equation of the regression line of \(w\) on \(v\), giving your equation in the form \(w = f ( v )\).

Question 3:
Part (a):
AnswerMarks Guidance
Vertical lines drawn from pointsM1 Or squares with correct sides
Best-fit line minimises squares of lengths of these linesA1 oe, clearly stated
[2]
Part (b)(i):
AnswerMarks Guidance
\(u = -3.55 + 2.05t\)M1 Evidence for correct method for \(b\) (e.g. right answer)
A1Both numbers right
A1All correct including letters
[3]
Part (b)(ii):
AnswerMarks Guidance
\(w - 4 = -3.55 + 2.05t/2\)M1 Put \(t = v/2,\ u = w - 4\)
\(w = 0.45 + 1.025v\)A1 Fully correct, simplified to 3 terms
[2]
## Question 3:

### Part (a):
Vertical lines drawn from points | **M1** | Or squares with correct sides
Best-fit line minimises squares of lengths of these lines | **A1** | oe, clearly stated
[2]

### Part (b)(i):
$u = -3.55 + 2.05t$ | **M1** | Evidence for correct method for $b$ (e.g. right answer)
| **A1** | Both numbers right
| **A1** | All correct including letters
[3]

### Part (b)(ii):
$w - 4 = -3.55 + 2.05t/2$ | **M1** | Put $t = v/2,\ u = w - 4$
$w = 0.45 + 1.025v$ | **A1** | Fully correct, simplified to 3 terms
[2]

---
3
\begin{enumerate}[label=(\alph*)]
\item Using the scatter diagram in the Printed Answer Booklet, explain what is meant by least squares in the context of a regression line of $y$ on $x$.
\item A set of bivariate data $( t , u )$ is summarised as follows.\\
$n = 5 \quad \sum t = 35 \quad \sum u = 54$\\
$\sum t ^ { 2 } = 285 \quad \sum u ^ { 2 } = 758 \quad \sum \mathrm { tu } = 460$
\begin{enumerate}[label=(\roman*)]
\item Calculate the equation of the regression line of $u$ on $t$.
\item The variables $t$ and $u$ are now scaled using the following scaling.\\
$\mathrm { v } = 2 \mathrm { t } , \mathrm { w } = \mathrm { u } + 4$\\
Find the equation of the regression line of $w$ on $v$, giving your equation in the form $w = f ( v )$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{OCR Further Statistics AS 2021 Q3 [7]}}