OCR Further Statistics AS 2024 June — Question 1 8 marks

Exam BoardOCR
ModuleFurther Statistics AS (Further Statistics AS)
Year2024
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicUniform Distribution
TypeVariance of linear transformation
DifficultyModerate -0.8 This is a straightforward Further Statistics question testing basic properties of expectation and variance with discrete distributions. Part (a) uses E(aX)=aE(X), part (b) uses Var(aX)=a²Var(X), part (c) requires equating E and Var formulas (routine algebra), and part (d) is standard variance calculation from a probability distribution. All parts are direct applications of standard formulas with minimal problem-solving required.
Spec5.02a Discrete probability distributions: general5.02b Expectation and variance: discrete random variables

1 The random variable \(W\) can take values 1,2 or 3 and has a discrete uniform distribution.
  1. Write down the value of \(\mathrm { E } ( 2 W )\).
  2. Find the value of \(\operatorname { Var } ( 2 W )\).
  3. Determine the value of the constant \(k\) for which \(\mathrm { E } ( 2 \mathrm {~W} + \mathrm { k } ) = \operatorname { Var } ( 2 \mathrm {~W} + \mathrm { k } )\). The random variable \(S\) has the probability distribution shown in the following table.
    \(S\)23456
    \(P ( S = S )\)\(\frac { 2 } { 9 }\)\(\frac { 1 } { 9 }\)\(\frac { 1 } { 3 }\)\(\frac { 1 } { 9 }\)\(\frac { 2 } { 9 }\)
  4. Calculate \(\operatorname { Var } ( S )\).

Question 1:
Part (a)
AnswerMarks Guidance
\(4\)B1 [1] Exact, allow 4.00
Part (b)
AnswerMarks Guidance
\(4 \times \text{Var}(W)\) or \(\Sigma 4w^2 P(w) - 4^2\)M1 Can be implied by answer
\(\frac{8}{3}\)A1 [2] Can be written down, exact or awrt 2.67
Part (c)
AnswerMarks Guidance
\(4 + k = \frac{8}{3}\)M1 Use *their* (a) \(+ k =\) *their* (b)
\(k = -\frac{4}{3}\)A1 [2] Exact or awrt \(-1.33\)
Part (d)
AnswerMarks Guidance
\(\Sigma s^2 P(s)\ (= 18)\)M1 Clear attempt at finding \(\Sigma s^2 P(s)\)
\(18 - 4^2\)M1 Subtract \(4^2\)
\(2\)A1 [3] Exact, allow 2.00. Can scale variables, e.g. \(X = S - 3\): \(E(X^2) = \frac{18}{9} = 2\); \(E(X) = 0\); \(\text{Var}(S) = 2\)
# Question 1:

## Part (a)
$4$ | B1 [1] | Exact, allow 4.00

## Part (b)
$4 \times \text{Var}(W)$ or $\Sigma 4w^2 P(w) - 4^2$ | M1 | Can be implied by answer
$\frac{8}{3}$ | A1 [2] | Can be written down, exact or awrt 2.67

## Part (c)
$4 + k = \frac{8}{3}$ | M1 | Use *their* **(a)** $+ k =$ *their* **(b)**
$k = -\frac{4}{3}$ | A1 [2] | Exact or awrt $-1.33$

## Part (d)
$\Sigma s^2 P(s)\ (= 18)$ | M1 | Clear attempt at finding $\Sigma s^2 P(s)$
$18 - 4^2$ | M1 | Subtract $4^2$
$2$ | A1 [3] | Exact, allow 2.00. Can scale variables, e.g. $X = S - 3$: $E(X^2) = \frac{18}{9} = 2$; $E(X) = 0$; $\text{Var}(S) = 2$

---
1 The random variable $W$ can take values 1,2 or 3 and has a discrete uniform distribution.
\begin{enumerate}[label=(\alph*)]
\item Write down the value of $\mathrm { E } ( 2 W )$.
\item Find the value of $\operatorname { Var } ( 2 W )$.
\item Determine the value of the constant $k$ for which $\mathrm { E } ( 2 \mathrm {~W} + \mathrm { k } ) = \operatorname { Var } ( 2 \mathrm {~W} + \mathrm { k } )$.

The random variable $S$ has the probability distribution shown in the following table.

\begin{center}
\begin{tabular}{ | l | c | c | c | c | c | }
\hline
$S$ & 2 & 3 & 4 & 5 & 6 \\
\hline
$P ( S = S )$ & $\frac { 2 } { 9 }$ & $\frac { 1 } { 9 }$ & $\frac { 1 } { 3 }$ & $\frac { 1 } { 9 }$ & $\frac { 2 } { 9 }$ \\
\hline
\end{tabular}
\end{center}
\item Calculate $\operatorname { Var } ( S )$.
\end{enumerate}

\hfill \mbox{\textit{OCR Further Statistics AS 2024 Q1 [8]}}