OCR Further Pure Core AS 2022 June — Question 2 7 marks

Exam BoardOCR
ModuleFurther Pure Core AS (Further Pure Core AS)
Year2022
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMatrices
TypeConditions for unique solution
DifficultyModerate -0.3 Part (a) involves routine matrix operations (addition, multiplication, squaring) requiring only direct application of definitions. Part (b)(i) is straightforward determinant calculation and solving a linear equation. Part (b)(ii) requires understanding that no unique solution means determinant equals zero, then solving—this is standard A-level Further Maths content with no novel insight required. Overall slightly easier than average due to being mostly procedural.
Spec4.03b Matrix operations: addition, multiplication, scalar4.03h Determinant 2x2: calculation4.03r Solve simultaneous equations: using inverse matrix

2 Matrices \(\mathbf { A }\) and \(\mathbf { B }\) are given by \(\mathbf { A } = \left( \begin{array} { r r } a & 1 \\ - 1 & 3 \end{array} \right)\) and \(\mathbf { B } = \left( \begin{array} { l l } - 2 & 5 \\ - 1 & 0 \end{array} \right)\) where \(a\) is a constant.
  1. Find the following matrices.
    • \(\mathbf { A } + \mathbf { B }\)
    • AB
    • \(\mathbf { A } ^ { 2 }\)
      1. Given that the determinant of \(\mathbf { A }\) is 25 find the value of \(a\).
      2. You are given instead that the following system of equations does not have a unique solution.
    $$\begin{array} { r } a x + y = - 2 \\ - x + 3 y = - 6 \end{array}$$ Determine the value of \(a\).

Question 2:
Part (a):
AnswerMarks Guidance
AnswerMarks Guidance
\(A+B=\begin{pmatrix}a-2 & 6\\-2 & 3\end{pmatrix}\)B1 Any double signs must be simplified correctly
\(AB=\begin{pmatrix}-2a-1 & 5a\\-1 & -5\end{pmatrix}\)B1
\(A^2=\begin{pmatrix}a^2-1 & a+3\\-a-3 & 8\end{pmatrix}\)B1
[3]
Part (b)(i):
AnswerMarks Guidance
AnswerMarks Guidance
\((\det\mathbf{A}) = a\times3 - 1\times-1\)M1 Correct expansion of determinant of \(\mathbf{A}\)
\(3a+1=25 \Rightarrow a=8\)A1
[2]
Part (b)(ii):
AnswerMarks Guidance
AnswerMarks Guidance
System reduces to \(A\begin{pmatrix}x\\y\end{pmatrix}=\begin{pmatrix}-2\\-6\end{pmatrix}\) so no unique solution \(\Rightarrow (\det\mathbf{A})=3a+1=0\)M1 Setting their determinant to 0 if it is a linear function of \(a\). Answer only is ok here
\(\therefore a = -\frac{1}{3}\)A1
Alternative: Multiplying the first equation by 3 gives \(3ax+3y=-6\) and \(-x+3y=-6\). These two equations are the same if \(3a=-1 \Rightarrow a=\dfrac{-1}{3}\)M1, A1 Or subtracting gives \((3a+1)x=0 \rightarrow a=\dfrac{-1}{3}\)
[2]
# Question 2:

## Part (a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $A+B=\begin{pmatrix}a-2 & 6\\-2 & 3\end{pmatrix}$ | B1 | Any double signs must be simplified correctly |
| $AB=\begin{pmatrix}-2a-1 & 5a\\-1 & -5\end{pmatrix}$ | B1 | |
| $A^2=\begin{pmatrix}a^2-1 & a+3\\-a-3 & 8\end{pmatrix}$ | B1 | |
| **[3]** | | |

## Part (b)(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $(\det\mathbf{A}) = a\times3 - 1\times-1$ | M1 | Correct expansion of determinant of $\mathbf{A}$ |
| $3a+1=25 \Rightarrow a=8$ | A1 | |
| **[2]** | | |

## Part (b)(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| System reduces to $A\begin{pmatrix}x\\y\end{pmatrix}=\begin{pmatrix}-2\\-6\end{pmatrix}$ so no unique solution $\Rightarrow (\det\mathbf{A})=3a+1=0$ | M1 | Setting their determinant to 0 if it is a linear function of $a$. Answer only is ok here |
| $\therefore a = -\frac{1}{3}$ | A1 | |
| **Alternative:** Multiplying the first equation by 3 gives $3ax+3y=-6$ and $-x+3y=-6$. These two equations are the same if $3a=-1 \Rightarrow a=\dfrac{-1}{3}$ | M1, A1 | Or subtracting gives $(3a+1)x=0 \rightarrow a=\dfrac{-1}{3}$ |
| **[2]** | | |

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2 Matrices $\mathbf { A }$ and $\mathbf { B }$ are given by $\mathbf { A } = \left( \begin{array} { r r } a & 1 \\ - 1 & 3 \end{array} \right)$ and $\mathbf { B } = \left( \begin{array} { l l } - 2 & 5 \\ - 1 & 0 \end{array} \right)$ where $a$ is a constant.
\begin{enumerate}[label=(\alph*)]
\item Find the following matrices.

\begin{itemize}
  \item $\mathbf { A } + \mathbf { B }$
  \item AB
  \item $\mathbf { A } ^ { 2 }$
\item \begin{enumerate}[label=(\roman*)]
\item Given that the determinant of $\mathbf { A }$ is 25 find the value of $a$.
\item You are given instead that the following system of equations does not have a unique solution.
\end{itemize}

$$\begin{array} { r } 
a x + y = - 2 \\
- x + 3 y = - 6
\end{array}$$

Determine the value of $a$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{OCR Further Pure Core AS 2022 Q2 [7]}}