CAIE Further Paper 1 2020 November — Question 7 17 marks

Exam BoardCAIE
ModuleFurther Paper 1 (Further Paper 1)
Year2020
SessionNovember
Marks17
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolar coordinates
TypeConvert Cartesian to polar equation
DifficultyChallenging +1.2 This is a multi-part Further Maths polar coordinates question requiring standard conversions (x=r cos θ, y=r sin θ), sketching, area integration using the standard formula, and optimization using a given identity. While it involves several techniques and is from Further Maths, each part follows well-established procedures without requiring novel insight—the conversion is algebraic manipulation, the area uses the memorized formula ½∫r²dθ, and part (d) provides the key identity needed. Slightly above average difficulty due to the algebraic complexity and multi-step nature, but not exceptionally challenging.
Spec1.05l Double angle formulae: and compound angle formulae4.09a Polar coordinates: convert to/from cartesian4.09b Sketch polar curves: r = f(theta)4.09c Area enclosed: by polar curve

7
  1. Show that the curve with Cartesian equation $$\left( x ^ { 2 } + y ^ { 2 } \right) ^ { \frac { 5 } { 2 } } = 4 x y \left( x ^ { 2 } - y ^ { 2 } \right)$$ has polar equation \(r = \sin 4 \theta\).
    The curve \(C\) has polar equation \(r = \sin 4 \theta\), for \(0 \leqslant \theta \leqslant \frac { 1 } { 4 } \pi\).
  2. Sketch \(C\) and state the equation of the line of symmetry.
  3. Find the exact value of the area of the region enclosed by \(C\).
  4. Using the identity \(\sin 4 \theta \equiv 4 \sin \theta \cos ^ { 3 } \theta - 4 \sin ^ { 3 } \theta \cos \theta\), find the maximum distance of \(C\) from the line \(\theta = \frac { 1 } { 2 } \pi\). Give your answer correct to 2 decimal places.
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

Question 7(a):
AnswerMarks Guidance
AnswerMarks Guidance
\(r^5 = 4xy(x^2 - y^2)\)B1 Uses \(r^2 = x^2 + y^2\)
\(r^5 = 4r^4\cos\theta\sin\theta(\cos^2\theta - \sin^2\theta)\)B1 Uses \(x = r\cos\theta\) and \(y = r\sin\theta\)
\(r = 2\sin 2\theta\cos 2\theta\)M1 Applies at least one double angle formula
\(r = \sin 4\theta\)A1 Applies both double angle formulae, AG
Total: 4
Question 7(b):
AnswerMarks Guidance
AnswerMarks Guidance
[Initial line drawn and one loop in first quadrant]B1 Initial line drawn and one loop in first quadrant
[Correct shape at extremities]B1 Correct shape at extremities
\(\theta = \frac{1}{8}\pi\)B1 States the equation of the line of symmetry
Total: 3
Question 7(c):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{1}{2}\int_0^{\frac{1}{4}\pi}\sin^2 4\theta\, \mathrm{d}\theta\)M1 Uses \(\frac{1}{2}\int r^2\,\mathrm{d}\theta\) with correct limits
\(= \frac{1}{4}\int_0^{\frac{1}{4}\pi} 1 - \cos 8\theta\,\mathrm{d}\theta = \frac{1}{4}\left[\theta - \frac{1}{8}\sin 8\theta\right]_0^{\frac{1}{4}\pi}\)M1 A1 Applies double angle formula and integrates
\(= \frac{1}{16}\pi\)A1
Total: 4
Question 7(d):
AnswerMarks Guidance
AnswerMarks Guidance
\(x = 4(\sin\theta\cos^4\theta - \sin^3\theta\cos^2\theta)\)B1 Uses \(x = r\cos\theta\)
\(-4\sin^2\theta\cos^3\theta + \cos^5\theta + 2\sin^4\theta\cos\theta - 3\sin^2\theta\cos^3\theta = 0\)M1 Differentiates and sets equal to 0
\(\cos\theta(2\sin^4\theta - 7\sin^2\theta\cos^2\theta + \cos^4\theta) = 0\)A1
\(\cos\theta = 0\) or \(2\tan^4\theta - 7\tan^2\theta + 1 = 0\)M1 Forms quadratic in \(\tan^2\theta\); must see consideration of \(\cos\theta = 0\)
\(\tan^2\theta = \frac{1}{4}(7 \pm \sqrt{41}) \Rightarrow \theta = \pm 0.369, \pm 1.071\)B1 Allow use of decimals
\(\theta = 0.369 \Rightarrow x = 0.93\) (or \(\theta = -0.369 \Rightarrow \x\ = 0.93\))
Total: 6
## Question 7(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $r^5 = 4xy(x^2 - y^2)$ | B1 | Uses $r^2 = x^2 + y^2$ |
| $r^5 = 4r^4\cos\theta\sin\theta(\cos^2\theta - \sin^2\theta)$ | B1 | Uses $x = r\cos\theta$ and $y = r\sin\theta$ |
| $r = 2\sin 2\theta\cos 2\theta$ | M1 | Applies at least one double angle formula |
| $r = \sin 4\theta$ | A1 | Applies both double angle formulae, AG |
| **Total: 4** | | |

## Question 7(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| [Initial line drawn and one loop in first quadrant] | B1 | Initial line drawn and one loop in first quadrant |
| [Correct shape at extremities] | B1 | Correct shape at extremities |
| $\theta = \frac{1}{8}\pi$ | B1 | States the equation of the line of symmetry |
| **Total: 3** | | |

## Question 7(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{1}{2}\int_0^{\frac{1}{4}\pi}\sin^2 4\theta\, \mathrm{d}\theta$ | M1 | Uses $\frac{1}{2}\int r^2\,\mathrm{d}\theta$ with correct limits |
| $= \frac{1}{4}\int_0^{\frac{1}{4}\pi} 1 - \cos 8\theta\,\mathrm{d}\theta = \frac{1}{4}\left[\theta - \frac{1}{8}\sin 8\theta\right]_0^{\frac{1}{4}\pi}$ | M1 A1 | Applies double angle formula and integrates |
| $= \frac{1}{16}\pi$ | A1 | |
| **Total: 4** | | |

## Question 7(d):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $x = 4(\sin\theta\cos^4\theta - \sin^3\theta\cos^2\theta)$ | B1 | Uses $x = r\cos\theta$ |
| $-4\sin^2\theta\cos^3\theta + \cos^5\theta + 2\sin^4\theta\cos\theta - 3\sin^2\theta\cos^3\theta = 0$ | M1 | Differentiates and sets equal to 0 |
| $\cos\theta(2\sin^4\theta - 7\sin^2\theta\cos^2\theta + \cos^4\theta) = 0$ | A1 | |
| $\cos\theta = 0$ or $2\tan^4\theta - 7\tan^2\theta + 1 = 0$ | M1 | Forms quadratic in $\tan^2\theta$; must see consideration of $\cos\theta = 0$ |
| $\tan^2\theta = \frac{1}{4}(7 \pm \sqrt{41}) \Rightarrow \theta = \pm 0.369, \pm 1.071$ | B1 | Allow use of decimals |
| $\theta = 0.369 \Rightarrow x = 0.93$ (or $\theta = -0.369 \Rightarrow \|x\| = 0.93$) | A1 | Substituting $\theta = \pm 0.369$ gives maximum value of $\|x\|$ |
| **Total: 6** | | |
7
\begin{enumerate}[label=(\alph*)]
\item Show that the curve with Cartesian equation

$$\left( x ^ { 2 } + y ^ { 2 } \right) ^ { \frac { 5 } { 2 } } = 4 x y \left( x ^ { 2 } - y ^ { 2 } \right)$$

has polar equation $r = \sin 4 \theta$.\\

The curve $C$ has polar equation $r = \sin 4 \theta$, for $0 \leqslant \theta \leqslant \frac { 1 } { 4 } \pi$.
\item Sketch $C$ and state the equation of the line of symmetry.
\item Find the exact value of the area of the region enclosed by $C$.
\item Using the identity $\sin 4 \theta \equiv 4 \sin \theta \cos ^ { 3 } \theta - 4 \sin ^ { 3 } \theta \cos \theta$, find the maximum distance of $C$ from the line $\theta = \frac { 1 } { 2 } \pi$. Give your answer correct to 2 decimal places.\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.
\end{enumerate}

\hfill \mbox{\textit{CAIE Further Paper 1 2020 Q7 [17]}}