Easy -1.2 This is a straightforward application of the circular motion formula F = mv²/r with all values given directly. It requires only substitution into a single formula (40 × 25 / 4 = 250 N) with no conceptual challenge, making it easier than average despite being Further Maths content. The multiple-choice format further reduces difficulty.
1 A child, of mass 40 kg , moves at constant speed of \(5 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) on a fairground ride.
The path of the child is a circle of radius 4 metres.
Find the magnitude of the resultant force acting on the child.
Circle your answer. [0pt]
[1 mark]
6.3 N
50 N
130 N
250 N
1 A child, of mass 40 kg , moves at constant speed of $5 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ on a fairground ride.\\
The path of the child is a circle of radius 4 metres.\\
Find the magnitude of the resultant force acting on the child.\\
Circle your answer.\\[0pt]
[1 mark]\\
6.3 N\\
50 N\\
130 N\\
250 N
\hfill \mbox{\textit{AQA Further AS Paper 2 Mechanics Q1 [1]}}