AQA Further AS Paper 2 Mechanics 2020 June — Question 2 1 marks

Exam BoardAQA
ModuleFurther AS Paper 2 Mechanics (Further AS Paper 2 Mechanics)
Year2020
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAdvanced work-energy problems
TypeWork done by non-constant force integration
DifficultyModerate -0.8 This is a straightforward application of the work integral W = ∫F dx with a simple polynomial force function. Students need only recall the definition and integrate 6x² from 1 to 2, giving [2x³]₁² = 16 - 2 = 14J. It's a single-step calculation with no problem-solving required, and the multiple-choice format removes any presentation demands. Below average difficulty even for Further Maths.
Spec6.02c Work by variable force: using integration

2 An object moves under the action of a single force \(F\) newtons.
It is given that \(F = 6 x ^ { 2 }\), where \(x\) represents the displacement in metres from the initial position of the object. Find the work done by \(F\) in moving the object from \(x = 1\) to \(x = 2\) Circle your answer.
[0pt] [1 mark]
12 J
14 J
18J
42 J

Question 2:
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(14 \text{ J}\)B1 Circles correct answer
Total: 1 mark
## Question 2:

| Answer/Working | Mark | Guidance |
|---|---|---|
| $14 \text{ J}$ | B1 | Circles correct answer |

**Total: 1 mark**

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2 An object moves under the action of a single force $F$ newtons.\\
It is given that $F = 6 x ^ { 2 }$, where $x$ represents the displacement in metres from the initial position of the object.

Find the work done by $F$ in moving the object from $x = 1$ to $x = 2$

Circle your answer.\\[0pt]
[1 mark]\\
12 J\\
14 J\\
18J\\
42 J

\hfill \mbox{\textit{AQA Further AS Paper 2 Mechanics 2020 Q2 [1]}}