OCR MEI Paper 3 Specimen — Question 2 4 marks

Exam BoardOCR MEI
ModulePaper 3 (Paper 3)
SessionSpecimen
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGeneralised Binomial Theorem
TypeExpand and state validity
DifficultyModerate -0.5 This is a straightforward application of the binomial expansion formula for fractional powers with standard validity condition |2x| < 1. It requires direct substitution into the formula and simplification, making it slightly easier than average as it's a routine textbook exercise with no problem-solving element.
Spec1.04c Extend binomial expansion: rational n, |x|<11.04d Binomial expansion validity: convergence conditions

2 Find the first four terms of the binomial expansion of \(( 1 - 2 x ) ^ { \frac { 1 } { 2 } }\). State the set of values of \(x\) for which the expansion is valid.

Question 2:
AnswerMarks Guidance
\((1-2x)^{\frac{1}{2}} \approx 1 + \frac{\frac{1}{2}\left(-\frac{1}{2}\right)}{2!}(-2x)^2 + \frac{\frac{1}{2}\left(-\frac{1}{2}\right)\left(-\frac{3}{2}\right)}{3!}(-2x)^3\)M1 AO 1.1
\(= 1 - x - \frac{1}{2}x^2 - \frac{1}{2}x^3\)A2 AO 1.1, 1.1
Valid for \(-\frac{1}{2} < x < \frac{1}{2}\)B1 AO 2.3
[4 marks]
## Question 2:

$(1-2x)^{\frac{1}{2}} \approx 1 + \frac{\frac{1}{2}\left(-\frac{1}{2}\right)}{2!}(-2x)^2 + \frac{\frac{1}{2}\left(-\frac{1}{2}\right)\left(-\frac{3}{2}\right)}{3!}(-2x)^3$ | M1 | AO 1.1 | Binomial coefficients seen, allow one error

$= 1 - x - \frac{1}{2}x^2 - \frac{1}{2}x^3$ | A2 | AO 1.1, 1.1 | $1-x$, $-\frac{1}{2}x^2$, $-\frac{1}{2}x^3$ or A1 for 2 correct terms

Valid for $-\frac{1}{2} < x < \frac{1}{2}$ | B1 | AO 2.3 | or $|x| < \frac{1}{2}$; series converges for $x = \pm\frac{1}{2}$; candidates not expected to know this but allow $\leq$ for either or both inequalities

**[4 marks]**

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2 Find the first four terms of the binomial expansion of $( 1 - 2 x ) ^ { \frac { 1 } { 2 } }$.

State the set of values of $x$ for which the expansion is valid.

\hfill \mbox{\textit{OCR MEI Paper 3  Q2 [4]}}