OCR MEI Paper 3 2018 June — Question 1 3 marks

Exam BoardOCR MEI
ModulePaper 3 (Paper 3)
Year2018
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSine and Cosine Rules
TypeBasic cosine rule application
DifficultyEasy -1.2 This is a straightforward single-step application of the cosine rule to find one missing side, then add three sides for perimeter. The diagram provides two sides and the included angle, making this a routine textbook exercise requiring only direct formula substitution with no problem-solving or multi-step reasoning.
Spec2.02a Interpret single variable data: tables and diagrams

1 Triangle ABC is shown in Fig. 1. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{31bc8bde-8d37-4e97-94e2-e3e73aab55e9-4_451_565_520_744} \captionsetup{labelformat=empty} \caption{Fig. 1}
\end{figure} Find the perimeter of triangle ABC .

Question 1:
AnswerMarks Guidance
\([BC^2] = 32^2 + 14^2 - 2 \times 32 \times 14\cos85°\)M1 (3.1a) Use of cosine rule to find BC; 1141.9…
\([BC] = 33.8\) cmA1 (1.1) 33.79…
Perimeter \(= 79.8\) cmA1 (1.1) Accept 80 provided 3 or more sf seen as BC
**Question 1:**

$[BC^2] = 32^2 + 14^2 - 2 \times 32 \times 14\cos85°$ | M1 (3.1a) | Use of cosine rule to find BC; 1141.9…

$[BC] = 33.8$ cm | A1 (1.1) | 33.79…

Perimeter $= 79.8$ cm | A1 (1.1) | Accept 80 provided 3 or more sf seen as BC

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1 Triangle ABC is shown in Fig. 1.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{31bc8bde-8d37-4e97-94e2-e3e73aab55e9-4_451_565_520_744}
\captionsetup{labelformat=empty}
\caption{Fig. 1}
\end{center}
\end{figure}

Find the perimeter of triangle ABC .

\hfill \mbox{\textit{OCR MEI Paper 3 2018 Q1 [3]}}