OCR MEI AS Paper 2 2021 November — Question 8 4 marks

Exam BoardOCR MEI
ModuleAS Paper 2 (AS Paper 2)
Year2021
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors Introduction & 2D
TypeVector between two points
DifficultyEasy -1.2 This is a straightforward AS-level vectors question requiring only basic operations: finding a vector between two points using subtraction, calculating magnitude with Pythagoras, and checking collinearity by comparing scalar multiples. All steps are routine applications of standard formulas with no problem-solving insight needed.
Spec1.10d Vector operations: addition and scalar multiplication1.10f Distance between points: using position vectors

8 With respect to an origin O , the position vectors of the points A and B are \(\overrightarrow { \mathrm { OA } } = \binom { - 3 } { 20 }\) and \(\overrightarrow { \mathrm { OB } } = \binom { 6 } { 8 }\).
  1. Determine whether \(| \overrightarrow { \mathrm { AB } } | > 200\). The point C is such that \(\overrightarrow { \mathrm { AC } } = \binom { 18 } { - 24 }\).
  2. Determine whether \(\mathrm { A } , \mathrm { B }\) and C are collinear.

Question 8:
Part (a):
AnswerMarks Guidance
AnswerMark Guidance
\(\binom{6}{8} - \binom{-3}{20}\)M1 May see \(\binom{9}{-12}\) or \(\binom{-9}{12}\)
\(\\overrightarrow{AB}\ = 15\) or \(\sqrt{225}\) so \(\
[2]
Part (b):
AnswerMarks Guidance
AnswerMark Guidance
\(\overrightarrow{AC} = \binom{18}{-24} = 2 \times \binom{9}{-12}\)M1 FT their \(AB\); allow mark for comparison of their \(AB\) and \(AC\)
so \(A\), \(B\) and \(C\) are collinearA1
[2]
## Question 8:

### Part (a):
| Answer | Mark | Guidance |
|--------|------|----------|
| $\binom{6}{8} - \binom{-3}{20}$ | M1 | May see $\binom{9}{-12}$ or $\binom{-9}{12}$ |
| $\|\overrightarrow{AB}\| = 15$ or $\sqrt{225}$ so $\|\overrightarrow{AB}\| < 200$ or $\|AB\|$ is not greater than 200 | A1 | May see $\sqrt{9^2 + (-12)^2}$ oe. CWO |
| **[2]** | | |

### Part (b):
| Answer | Mark | Guidance |
|--------|------|----------|
| $\overrightarrow{AC} = \binom{18}{-24} = 2 \times \binom{9}{-12}$ | M1 | FT their $AB$; allow mark for comparison of their $AB$ and $AC$ |
| so $A$, $B$ and $C$ are collinear | A1 | |
| **[2]** | | |

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8 With respect to an origin O , the position vectors of the points A and B are\\
$\overrightarrow { \mathrm { OA } } = \binom { - 3 } { 20 }$ and $\overrightarrow { \mathrm { OB } } = \binom { 6 } { 8 }$.
\begin{enumerate}[label=(\alph*)]
\item Determine whether $| \overrightarrow { \mathrm { AB } } | > 200$.

The point C is such that $\overrightarrow { \mathrm { AC } } = \binom { 18 } { - 24 }$.
\item Determine whether $\mathrm { A } , \mathrm { B }$ and C are collinear.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI AS Paper 2 2021 Q8 [4]}}