OCR MEI AS Paper 2 2024 June — Question 9 6 marks

Exam BoardOCR MEI
ModuleAS Paper 2 (AS Paper 2)
Year2024
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProbability Definitions
TypeBasic probability calculation
DifficultyEasy -1.3 This is a straightforward probability question requiring basic counting and understanding of even/odd numbers and primes. Parts (a)-(c) are simple identification from a small sample space, while part (d) requires recognizing that sum is even when both rolls have same parity, but still involves only basic probability multiplication—well below average A-level difficulty.
Spec2.03a Mutually exclusive and independent events

9 A fair six-sided die has its faces numbered 1, 3, 4, 5, 6 and 7. The die is rolled once. \(A\) is the event that the die shows an even number. \(B\) is the event that the die shows a prime number.
  1. Write down the value of \(\mathrm { p } ( A )\).
  2. Write down the value of \(\mathrm { p } ( B )\).
  3. Write down the value of \(\mathrm { p } ( A\) or \(B )\). The die is rolled again.
  4. Calculate the probability that the sum of the scores from the two rolls is even.

Question 9:
Part (a):
AnswerMarks Guidance
AnswerMark Guidance
\(p(A) = \frac{1}{3}\) o.e.B1 e.g. \(\frac{2}{6}\) etc
Part (b):
AnswerMarks Guidance
AnswerMark Guidance
\(p(B) = \frac{1}{2}\) o.e.B1 e.g. \(\frac{3}{6}\) etc
Part (c):
AnswerMarks Guidance
AnswerMark Guidance
\(\frac{5}{6}\)B1FT FT their \(\frac{1}{3} + \frac{1}{2}\) provided their probability total \(\leq 1\)
Part (d):
AnswerMarks Guidance
AnswerMark Guidance
\(p(\text{odd, odd}) + p(\text{even, even})\) soi or \(1 - p(\text{odd, even})\) etcM1 Can score this mark for the intention to calculate \(p(\text{odd, odd}) + p(\text{even, even})\) - may be stated, or partial cases listed, or with a tree diagram with correct pathways or with a statement of 'odd, odd' and 'even, even' and an attempt to add.
\(\left(\frac{2}{3}\right)^2 + \left(\frac{1}{3}\right)^2\)A1
\(\frac{5}{9}\) o.e. \(\frac{20}{36}\) etcA1 allow \(0.\dot{5}\) correct to 3 dp or better so \(0.555\ldots\) or \(0.555\) but not \(0.55\) however isw once \(\frac{5}{9}\) o.e. seen. Condone \(0.556\)
Mark Scheme Extraction
Question (Probability - Sample Space):
Alternative 1:
AnswerMarks Guidance
AnswerMarks Guidance
Complete sample space diagram (as shown with sums of two dice ranging from 2 to 14)M1 3.1a - Complete sample space diagram with maximum two errors
Extraction of even outcomes (underlined values in diagram)A1 2.1 - Extraction of even outcomes - may circle or underline etc.
\(\frac{5}{9}\) o.e. \(\frac{20}{36}\) etcA1 1.1 - Allow \(0.\dot{5}\) correct to 3 dp or better so 0.555… or 0.555 but not 0.55 however isw once \(\frac{5}{9}\) o.e. seen. Condone 0.556
Alternative 2:
AnswerMarks Guidance
AnswerMarks Guidance
Listing cases: \((1,3)\ (1,5)\ (1,7)\ (3,5)\ (3,7)\ (4,6)\ (5,7)\) x2 and \((1,1)\ (3,3)\ (4,4)\ (5,5)\ (6,6)\ (7,7)\)M1 3.1a - Must make a clear attempt at pairing odd with odd and even with even. List can be incomplete for this mark
A complete list extractedA1 2.1 - May be implied by a correct answer
\(\frac{5}{9}\) o.e. \(\frac{20}{36}\) etcA1 1.1 - Allow \(0.\dot{5}\) correct to 3 dp or better so 0.555… but not 0.55 however isw once \(\frac{5}{9}\) o.e. seen. Condone 0.556
Total: [3]
## Question 9:

### Part (a):
| Answer | Mark | Guidance |
|--------|------|----------|
| $p(A) = \frac{1}{3}$ o.e. | B1 | e.g. $\frac{2}{6}$ etc |

### Part (b):
| Answer | Mark | Guidance |
|--------|------|----------|
| $p(B) = \frac{1}{2}$ o.e. | B1 | e.g. $\frac{3}{6}$ etc |

### Part (c):
| Answer | Mark | Guidance |
|--------|------|----------|
| $\frac{5}{6}$ | B1FT | FT their $\frac{1}{3} + \frac{1}{2}$ provided their probability total $\leq 1$ |

### Part (d):
| Answer | Mark | Guidance |
|--------|------|----------|
| $p(\text{odd, odd}) + p(\text{even, even})$ soi or $1 - p(\text{odd, even})$ etc | M1 | Can score this mark for the intention to calculate $p(\text{odd, odd}) + p(\text{even, even})$ - may be stated, or partial cases listed, or with a tree diagram with correct pathways or with a statement of 'odd, odd' and 'even, even' and an attempt to add. |
| $\left(\frac{2}{3}\right)^2 + \left(\frac{1}{3}\right)^2$ | A1 | |
| $\frac{5}{9}$ o.e. $\frac{20}{36}$ etc | A1 | allow $0.\dot{5}$ correct to 3 dp or better so $0.555\ldots$ or $0.555$ but not $0.55$ however isw once $\frac{5}{9}$ o.e. seen. Condone $0.556$ |

# Mark Scheme Extraction

## Question (Probability - Sample Space):

**Alternative 1:**

| Answer | Marks | Guidance |
|--------|-------|----------|
| Complete sample space diagram (as shown with sums of two dice ranging from 2 to 14) | M1 | 3.1a - Complete sample space diagram with maximum two errors |
| Extraction of even outcomes (underlined values in diagram) | A1 | 2.1 - Extraction of even outcomes - may circle or underline etc. |
| $\frac{5}{9}$ o.e. $\frac{20}{36}$ etc | A1 | 1.1 - Allow $0.\dot{5}$ correct to 3 dp or better so 0.555… or 0.555 but not 0.55 however isw once $\frac{5}{9}$ o.e. seen. Condone 0.556 |

**Alternative 2:**

| Answer | Marks | Guidance |
|--------|-------|----------|
| Listing cases: $(1,3)\ (1,5)\ (1,7)\ (3,5)\ (3,7)\ (4,6)\ (5,7)$ x2 and $(1,1)\ (3,3)\ (4,4)\ (5,5)\ (6,6)\ (7,7)$ | M1 | 3.1a - Must make a clear attempt at pairing odd with odd **and** even with even. List can be incomplete for this mark |
| A complete list extracted | A1 | 2.1 - May be implied by a correct answer |
| $\frac{5}{9}$ o.e. $\frac{20}{36}$ etc | A1 | 1.1 - Allow $0.\dot{5}$ correct to 3 dp or better so 0.555… but not 0.55 however isw once $\frac{5}{9}$ o.e. seen. Condone 0.556 |

**Total: [3]**

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9 A fair six-sided die has its faces numbered 1, 3, 4, 5, 6 and 7. The die is rolled once.\\
$A$ is the event that the die shows an even number.\\
$B$ is the event that the die shows a prime number.
\begin{enumerate}[label=(\alph*)]
\item Write down the value of $\mathrm { p } ( A )$.
\item Write down the value of $\mathrm { p } ( B )$.
\item Write down the value of $\mathrm { p } ( A$ or $B )$.

The die is rolled again.
\item Calculate the probability that the sum of the scores from the two rolls is even.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI AS Paper 2 2024 Q9 [6]}}