| Exam Board | OCR MEI |
|---|---|
| Module | AS Paper 1 (AS Paper 1) |
| Year | 2021 |
| Session | November |
| Marks | 10 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Newton's laws and connected particles |
| Type | Vertically connected particles, air resistance |
| Difficulty | Moderate -0.3 This is a standard connected particles problem with clear setup and straightforward application of Newton's second law. Parts (a)-(b) test modeling assumptions (routine recall), parts (c)-(f) involve drawing force diagrams and solving F=ma equations with given values. The two-stage approach (combined system then individual particle) is a textbook technique, making this slightly easier than average despite being multi-part. |
| Spec | 3.03a Force: vector nature and diagrams3.03d Newton's second law: 2D vectors3.03n Equilibrium in 2D: particle under forces |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| The size/shape of the women are not taken into account | E1 [1] | Allow: women are modelled as point masses. Allow model only involves their mass/weight |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| The mass (weight) of the rope is negligible [compared to that of the women] | E1 [1] | Allow either mass or weight used. Allow "no weight" oe |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| Draw and label correct weights (\(1500\) N upward, \(65g\) N and \(T\) at junction, \(75g\) N downward) | B1 | Draw and label the correct weights |
| Draw and label the given tension and the tension in the second rope. No extra forces | B1 [2] | — |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| Total mass \(140\) kg; \(1500 - 65g - 75g = 140a\) | M1, A1 [2] | Attempt to form N2L equation with \((65+75)a\). Condone one missing force. All correct |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(a = \frac{32}{35} = 0.914\ \text{m s}^{-2}\) | B1 [1] | cao. Allow from the solution of two separate equations |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| N2L for rescued woman: \(T - 75g = 75 \times \frac{32}{35}\) | M1 | Attempt to form an equation for the rescued woman (mass 75 kg). Equation must include \(T\) |
| Correct equation FT their \(a\) | A1 | — |
| \(T = \frac{5625}{7} = 804\) N | A1 [3] | Correct value for \(T\). Allow for 800 N from a correct equation |
| Alternative: N2L for rescue worker: \(1500 - 65g - T = 65 \times \frac{32}{35}\); \(T = \frac{5625}{7} = 804\) N | M1, A1, A1 | Attempt to form equation for rescue worker (mass 65 kg). Equation must include \(T\) |
# Question 10(a):
| Answer | Marks | Guidance |
|--------|-------|----------|
| The size/shape of the women are not taken into account | E1 [1] | Allow: women are modelled as point masses. Allow model only involves their mass/weight |
---
# Question 10(b):
| Answer | Marks | Guidance |
|--------|-------|----------|
| The mass (weight) of the rope is negligible [compared to that of the women] | E1 [1] | Allow either mass or weight used. Allow "no weight" oe |
---
# Question 10(c):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Draw and label correct weights ($1500$ N upward, $65g$ N and $T$ at junction, $75g$ N downward) | B1 | Draw and label the correct weights |
| Draw and label the given tension and the tension in the second rope. No extra forces | B1 [2] | — |
---
# Question 10(d):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Total mass $140$ kg; $1500 - 65g - 75g = 140a$ | M1, A1 [2] | Attempt to form N2L equation with $(65+75)a$. Condone one missing force. All correct |
---
# Question 10(e):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $a = \frac{32}{35} = 0.914\ \text{m s}^{-2}$ | B1 [1] | cao. Allow from the solution of two separate equations |
---
# Question 10(f):
| Answer | Marks | Guidance |
|--------|-------|----------|
| N2L for rescued woman: $T - 75g = 75 \times \frac{32}{35}$ | M1 | Attempt to form an equation for the rescued woman (mass 75 kg). Equation must include $T$ |
| Correct equation FT their $a$ | A1 | — |
| $T = \frac{5625}{7} = 804$ N | A1 [3] | Correct value for $T$. Allow for 800 N from a correct equation |
| **Alternative:** N2L for rescue worker: $1500 - 65g - T = 65 \times \frac{32}{35}$; $T = \frac{5625}{7} = 804$ N | M1, A1, A1 | Attempt to form equation for rescue worker (mass 65 kg). Equation must include $T$ |
10 A rescue worker is lowered from a helicopter on a rope. She attaches a second rope to herself and to a woman in difficulties on the ground. The helicopter winches both women upwards with the rescued woman vertically below the rescue worker, as shown in the diagram.\\
\includegraphics[max width=\textwidth, alt={}, center]{5428eabf-431d-4db1-8c25-1f2b9570d9aa-6_509_460_408_262}
The model for this motion uses the following modelling assumptions:
\begin{itemize}
\item each woman can be modelled as a particle;
\item the ropes are both light and inextensible;
\item there is no air resistance to the motion;
\item the motion is in a vertical line.
\begin{enumerate}[label=(\alph*)]
\item Explain what it means when the women are each 'modelled as a particle'.
\item Explain what 'light' means in this context.
\end{itemize}
The tension in the rope to the helicopter is 1500 N . The rescue worker has a mass of 65 kg and the rescued woman has a mass of 75 kg .
\item Draw a diagram showing the forces on the two women.
\item Write down the equation of motion of the two women considered as a single particle.
\item Calculate the acceleration of the women.
\item Determine the tension in the rope connecting the two women.
\end{enumerate}
\hfill \mbox{\textit{OCR MEI AS Paper 1 2021 Q10 [10]}}