OCR MEI AS Paper 1 2021 November — Question 10 10 marks

Exam BoardOCR MEI
ModuleAS Paper 1 (AS Paper 1)
Year2021
SessionNovember
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNewton's laws and connected particles
TypeVertically connected particles, air resistance
DifficultyModerate -0.3 This is a standard connected particles problem with clear setup and straightforward application of Newton's second law. Parts (a)-(b) test modeling assumptions (routine recall), parts (c)-(f) involve drawing force diagrams and solving F=ma equations with given values. The two-stage approach (combined system then individual particle) is a textbook technique, making this slightly easier than average despite being multi-part.
Spec3.03a Force: vector nature and diagrams3.03d Newton's second law: 2D vectors3.03n Equilibrium in 2D: particle under forces

10 A rescue worker is lowered from a helicopter on a rope. She attaches a second rope to herself and to a woman in difficulties on the ground. The helicopter winches both women upwards with the rescued woman vertically below the rescue worker, as shown in the diagram. \includegraphics[max width=\textwidth, alt={}, center]{5428eabf-431d-4db1-8c25-1f2b9570d9aa-6_509_460_408_262} The model for this motion uses the following modelling assumptions:
  • each woman can be modelled as a particle;
  • the ropes are both light and inextensible;
  • there is no air resistance to the motion;
  • the motion is in a vertical line.
    1. Explain what it means when the women are each 'modelled as a particle'.
    2. Explain what 'light' means in this context.
The tension in the rope to the helicopter is 1500 N . The rescue worker has a mass of 65 kg and the rescued woman has a mass of 75 kg .
  • Draw a diagram showing the forces on the two women.
  • Write down the equation of motion of the two women considered as a single particle.
  • Calculate the acceleration of the women.
  • Determine the tension in the rope connecting the two women.

  • Question 10(a):
    AnswerMarks Guidance
    AnswerMarks Guidance
    The size/shape of the women are not taken into accountE1 [1] Allow: women are modelled as point masses. Allow model only involves their mass/weight
    Question 10(b):
    AnswerMarks Guidance
    AnswerMarks Guidance
    The mass (weight) of the rope is negligible [compared to that of the women]E1 [1] Allow either mass or weight used. Allow "no weight" oe
    Question 10(c):
    AnswerMarks Guidance
    AnswerMarks Guidance
    Draw and label correct weights (\(1500\) N upward, \(65g\) N and \(T\) at junction, \(75g\) N downward)B1 Draw and label the correct weights
    Draw and label the given tension and the tension in the second rope. No extra forcesB1 [2]
    Question 10(d):
    AnswerMarks Guidance
    AnswerMarks Guidance
    Total mass \(140\) kg; \(1500 - 65g - 75g = 140a\)M1, A1 [2] Attempt to form N2L equation with \((65+75)a\). Condone one missing force. All correct
    Question 10(e):
    AnswerMarks Guidance
    AnswerMarks Guidance
    \(a = \frac{32}{35} = 0.914\ \text{m s}^{-2}\)B1 [1] cao. Allow from the solution of two separate equations
    Question 10(f):
    AnswerMarks Guidance
    AnswerMarks Guidance
    N2L for rescued woman: \(T - 75g = 75 \times \frac{32}{35}\)M1 Attempt to form an equation for the rescued woman (mass 75 kg). Equation must include \(T\)
    Correct equation FT their \(a\)A1
    \(T = \frac{5625}{7} = 804\) NA1 [3] Correct value for \(T\). Allow for 800 N from a correct equation
    Alternative: N2L for rescue worker: \(1500 - 65g - T = 65 \times \frac{32}{35}\); \(T = \frac{5625}{7} = 804\) NM1, A1, A1 Attempt to form equation for rescue worker (mass 65 kg). Equation must include \(T\)
    # Question 10(a):
    
    | Answer | Marks | Guidance |
    |--------|-------|----------|
    | The size/shape of the women are not taken into account | E1 [1] | Allow: women are modelled as point masses. Allow model only involves their mass/weight |
    
    ---
    
    # Question 10(b):
    
    | Answer | Marks | Guidance |
    |--------|-------|----------|
    | The mass (weight) of the rope is negligible [compared to that of the women] | E1 [1] | Allow either mass or weight used. Allow "no weight" oe |
    
    ---
    
    # Question 10(c):
    
    | Answer | Marks | Guidance |
    |--------|-------|----------|
    | Draw and label correct weights ($1500$ N upward, $65g$ N and $T$ at junction, $75g$ N downward) | B1 | Draw and label the correct weights |
    | Draw and label the given tension and the tension in the second rope. No extra forces | B1 [2] | — |
    
    ---
    
    # Question 10(d):
    
    | Answer | Marks | Guidance |
    |--------|-------|----------|
    | Total mass $140$ kg; $1500 - 65g - 75g = 140a$ | M1, A1 [2] | Attempt to form N2L equation with $(65+75)a$. Condone one missing force. All correct |
    
    ---
    
    # Question 10(e):
    
    | Answer | Marks | Guidance |
    |--------|-------|----------|
    | $a = \frac{32}{35} = 0.914\ \text{m s}^{-2}$ | B1 [1] | cao. Allow from the solution of two separate equations |
    
    ---
    
    # Question 10(f):
    
    | Answer | Marks | Guidance |
    |--------|-------|----------|
    | N2L for rescued woman: $T - 75g = 75 \times \frac{32}{35}$ | M1 | Attempt to form an equation for the rescued woman (mass 75 kg). Equation must include $T$ |
    | Correct equation FT their $a$ | A1 | — |
    | $T = \frac{5625}{7} = 804$ N | A1 [3] | Correct value for $T$. Allow for 800 N from a correct equation |
    | **Alternative:** N2L for rescue worker: $1500 - 65g - T = 65 \times \frac{32}{35}$; $T = \frac{5625}{7} = 804$ N | M1, A1, A1 | Attempt to form equation for rescue worker (mass 65 kg). Equation must include $T$ |
    10 A rescue worker is lowered from a helicopter on a rope. She attaches a second rope to herself and to a woman in difficulties on the ground. The helicopter winches both women upwards with the rescued woman vertically below the rescue worker, as shown in the diagram.\\
    \includegraphics[max width=\textwidth, alt={}, center]{5428eabf-431d-4db1-8c25-1f2b9570d9aa-6_509_460_408_262}
    
    The model for this motion uses the following modelling assumptions:
    
    \begin{itemize}
      \item each woman can be modelled as a particle;
      \item the ropes are both light and inextensible;
      \item there is no air resistance to the motion;
      \item the motion is in a vertical line.
    \begin{enumerate}[label=(\alph*)]
    \item Explain what it means when the women are each 'modelled as a particle'.
    \item Explain what 'light' means in this context.
    \end{itemize}
    
    The tension in the rope to the helicopter is 1500 N . The rescue worker has a mass of 65 kg and the rescued woman has a mass of 75 kg .
    \item Draw a diagram showing the forces on the two women.
    \item Write down the equation of motion of the two women considered as a single particle.
    \item Calculate the acceleration of the women.
    \item Determine the tension in the rope connecting the two women.
    \end{enumerate}
    
    \hfill \mbox{\textit{OCR MEI AS Paper 1 2021 Q10 [10]}}