Edexcel Paper 3 2023 June — Question 2 4 marks

Exam BoardEdexcel
ModulePaper 3 (Paper 3)
Year2023
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNewton's laws and connected particles
TypeBlock on rough horizontal surface – accelerating (finding acceleration or applied force)
DifficultyModerate -0.8 This is a straightforward application of Newton's second law and friction concepts with clear horizontal forces. Part (a) is trivial (R = mg), part (b) uses F = ma directly, and part (c) applies F = μR. All steps are standard textbook exercises requiring only routine recall and substitution, making it easier than average.
Spec3.03b Newton's first law: equilibrium3.03f Weight: W=mg3.03l Newton's third law: extend to situations requiring force resolution3.03r Friction: concept and vector form3.03t Coefficient of friction: F <= mu*R model

2. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{f9dc8158-8ed8-4138-9c75-050cf52e6f7e-04_83_659_267_703} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} A particle \(P\) has mass 5 kg .
The particle is pulled along a rough horizontal plane by a horizontal force of magnitude 28 N . The only resistance to motion is a frictional force of magnitude \(F\) newtons, as shown in Figure 1.
  1. Find the magnitude of the normal reaction of the plane on \(P\) The particle is accelerating along the plane at \(1.4 \mathrm {~m} \mathrm {~s} ^ { - 2 }\)
  2. Find the value of \(F\) The coefficient of friction between \(P\) and the plane is \(\mu\)
  3. Find the value of \(\mu\), giving your answer to 2 significant figures.

Question 2:
Part (a)
AnswerMarks Guidance
AnswerMark Guidance
\(R = 5g = 49\) (N)B1 Allow either \(5g\) or \(49\). No penalty for using \(g = 9.81\) or \(10\). Ignore any working. Must be positive. B0 if \(m\) is involved. Could be seen on diagram.
Part (b)
AnswerMarks Guidance
AnswerMark Guidance
\(28 - F = 5 \times 1.4\)M1 Equation with correct terms, dimensionally correct, condone sign errors.
\(F = 21\)A1 cao but allow \(\frac{15g}{7}\). Ignore units.
Part (c)
AnswerMarks Guidance
AnswerMark Guidance
\(\mu = 0.43\) (2sf required)B1ft \(\mu = \frac{\text{their (b)}}{\text{their (a)}}\). Answer must be a positive number given to 2sf. B0 if \(g = 9.81\) or \(10\) used. Do not allow restarts. Allow \(\mu > 1\).
## Question 2:

**Part (a)**
| Answer | Mark | Guidance |
|--------|------|----------|
| $R = 5g = 49$ (N) | B1 | Allow either $5g$ or $49$. No penalty for using $g = 9.81$ or $10$. Ignore any working. Must be positive. B0 if $m$ is involved. Could be seen on diagram. |

**Part (b)**
| Answer | Mark | Guidance |
|--------|------|----------|
| $28 - F = 5 \times 1.4$ | M1 | Equation with correct terms, dimensionally correct, condone sign errors. |
| $F = 21$ | A1 | cao but allow $\frac{15g}{7}$. Ignore units. |

**Part (c)**
| Answer | Mark | Guidance |
|--------|------|----------|
| $\mu = 0.43$ (2sf required) | B1ft | $\mu = \frac{\text{their (b)}}{\text{their (a)}}$. Answer must be a positive number given to 2sf. B0 if $g = 9.81$ or $10$ used. Do not allow restarts. Allow $\mu > 1$. |

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2.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{f9dc8158-8ed8-4138-9c75-050cf52e6f7e-04_83_659_267_703}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

A particle $P$ has mass 5 kg .\\
The particle is pulled along a rough horizontal plane by a horizontal force of magnitude 28 N .

The only resistance to motion is a frictional force of magnitude $F$ newtons, as shown in Figure 1.
\begin{enumerate}[label=(\alph*)]
\item Find the magnitude of the normal reaction of the plane on $P$

The particle is accelerating along the plane at $1.4 \mathrm {~m} \mathrm {~s} ^ { - 2 }$
\item Find the value of $F$

The coefficient of friction between $P$ and the plane is $\mu$
\item Find the value of $\mu$, giving your answer to 2 significant figures.
\end{enumerate}

\hfill \mbox{\textit{Edexcel Paper 3 2023 Q2 [4]}}