| Exam Board | Edexcel |
|---|---|
| Module | Paper 3 (Paper 3) |
| Year | 2023 |
| Session | June |
| Marks | 3 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Constant acceleration (SUVAT) |
| Type | SUVAT single equation: straightforward find |
| Difficulty | Easy -1.8 This is a straightforward SUVAT question requiring direct substitution into standard equations (v = u + at and s = ut + ½at²) with no problem-solving or conceptual challenge. It's significantly easier than average A-level questions, being a basic mechanics drill exercise. |
| Spec | 3.02d Constant acceleration: SUVAT formulae |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| \(16\) (m s\(^{-1}\)) | B1 | cao. Must be positive. Ignore any working. |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| \(s = \frac{1}{2} \times 3.2 \times 5^2\) OR \(s = \frac{(0+16)}{2} \times 5\) OR \(s = (16 \times 5) - \frac{1}{2} \times 3.2 \times 5^2\) OR \(16^2 = 2 \times 3.2 \times s\) OR from v-t graph \(s = \frac{1}{2} \times 5 \times 16\) | M1 | Complete method to find equation in \(s\) only, possibly using their '16'. Allow 'reversed motion': use of \(s = vt - \frac{1}{2}at^2\) with \(v=0\), i.e. \(s = -\frac{1}{2} \times 3.2 \times 5^2\) can score M1, and \(s = -40\) so distance is 40 (m) can score A1 |
| \(s = 40\) (m) | A1 | cao. Must be positive. N.B. correct answer only in (b) can score both marks. |
## Question 1:
**Part (a)**
| Answer | Mark | Guidance |
|--------|------|----------|
| $16$ (m s$^{-1}$) | B1 | cao. Must be positive. Ignore any working. |
**Part (b)**
| Answer | Mark | Guidance |
|--------|------|----------|
| $s = \frac{1}{2} \times 3.2 \times 5^2$ **OR** $s = \frac{(0+16)}{2} \times 5$ **OR** $s = (16 \times 5) - \frac{1}{2} \times 3.2 \times 5^2$ **OR** $16^2 = 2 \times 3.2 \times s$ **OR** from v-t graph $s = \frac{1}{2} \times 5 \times 16$ | M1 | Complete method to find equation in $s$ only, possibly using their '16'. Allow 'reversed motion': use of $s = vt - \frac{1}{2}at^2$ with $v=0$, i.e. $s = -\frac{1}{2} \times 3.2 \times 5^2$ can score M1, and $s = -40$ so distance is 40 (m) can score A1 |
| $s = 40$ (m) | A1 | cao. Must be positive. N.B. correct answer only in (b) can score both marks. |
---\begin{enumerate}
\item A car is initially at rest on a straight horizontal road.
\end{enumerate}
The car then accelerates along the road with a constant acceleration of $3.2 \mathrm {~ms} ^ { - 2 }$\\
Find\\
(a) the speed of the car after 5 s ,\\
(b) the distance travelled by the car in the first 5 s .
\hfill \mbox{\textit{Edexcel Paper 3 2023 Q1 [3]}}