Edexcel Paper 2 Specimen — Question 7 5 marks

Exam BoardEdexcel
ModulePaper 2 (Paper 2)
SessionSpecimen
Marks5
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Mark schemeDownload PDF ↗
TopicGeneralised Binomial Theorem
TypeExpand and state validity
DifficultyModerate -0.3 This is a straightforward application of the binomial expansion with a fractional power, requiring rewriting as 2(1-x/4)^(1/2), expanding to find k, and checking validity |x/4|<1. The validity check is routine. Slightly easier than average due to being a standard textbook exercise with clear steps.
Spec1.04c Extend binomial expansion: rational n, |x|<11.04d Binomial expansion validity: convergence conditions

  1. (a) Use the binomial expansion, in ascending powers of \(x\), to show that
$$\sqrt { ( 4 - x ) } = 2 - \frac { 1 } { 4 } x + k x ^ { 2 } + \ldots$$ where \(k\) is a rational constant to be found. A student attempts to substitute \(x = 1\) into both sides of this equation to find an approximate value for \(\sqrt { 3 }\).
(b) State, giving a reason, if the expansion is valid for this value of \(x\).

Question 7(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\sqrt{(4-x)} = 2\left(1 - \frac{1}{4}x\right)^{\frac{1}{2}}\)M1 Take out factor of 4; write as \(2(1\pm\ldots)^{\frac{1}{2}}\)
\(\left(1-\frac{1}{4}x\right)^{\frac{1}{2}} = 1 + \frac{1}{2}\left(-\frac{1}{4}x\right) + \frac{\left(\frac{1}{2}\right)\left(-\frac{1}{2}\right)}{2!}\left(-\frac{1}{4}x\right)^2 + \ldots\)M1 Attempt binomial expansion with \(n = \frac{1}{2}\)
\(\sqrt{(4-x)} = 2\left(1 - \frac{1}{8}x - \frac{1}{128}x^2 + \ldots\right)\)A1 Correct expression inside bracket (may be unsimplified)
\(\sqrt{(4-x)} = 2 - \frac{1}{4}x - \frac{1}{64}x^2 + \ldots\) and \(k = -\frac{1}{64}\)A1 Fully simplified with correct \(k\)
Question 7(b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
The expansion is valid for \(x < 4\), so \(x=1\) can be used
## Question 7(a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\sqrt{(4-x)} = 2\left(1 - \frac{1}{4}x\right)^{\frac{1}{2}}$ | M1 | Take out factor of 4; write as $2(1\pm\ldots)^{\frac{1}{2}}$ |
| $\left(1-\frac{1}{4}x\right)^{\frac{1}{2}} = 1 + \frac{1}{2}\left(-\frac{1}{4}x\right) + \frac{\left(\frac{1}{2}\right)\left(-\frac{1}{2}\right)}{2!}\left(-\frac{1}{4}x\right)^2 + \ldots$ | M1 | Attempt binomial expansion with $n = \frac{1}{2}$ |
| $\sqrt{(4-x)} = 2\left(1 - \frac{1}{8}x - \frac{1}{128}x^2 + \ldots\right)$ | A1 | Correct expression inside bracket (may be unsimplified) |
| $\sqrt{(4-x)} = 2 - \frac{1}{4}x - \frac{1}{64}x^2 + \ldots$ and $k = -\frac{1}{64}$ | A1 | Fully simplified with correct $k$ |

## Question 7(b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| The expansion is valid for $|x| < 4$, so $x=1$ can be used | B1 | Must state valid range $|x|<4$ and confirm $x=1$ satisfies it |
\begin{enumerate}
  \item (a) Use the binomial expansion, in ascending powers of $x$, to show that
\end{enumerate}

$$\sqrt { ( 4 - x ) } = 2 - \frac { 1 } { 4 } x + k x ^ { 2 } + \ldots$$

where $k$ is a rational constant to be found.

A student attempts to substitute $x = 1$ into both sides of this equation to find an approximate value for $\sqrt { 3 }$.\\
(b) State, giving a reason, if the expansion is valid for this value of $x$.

\hfill \mbox{\textit{Edexcel Paper 2  Q7 [5]}}