| Exam Board | Edexcel |
|---|---|
| Module | Paper 2 (Paper 2) |
| Year | 2021 |
| Session | October |
| Marks | 3 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Laws of Logarithms |
| Type | Solve ln equation using subtraction law |
| Difficulty | Moderate -0.3 This is a straightforward application of logarithm laws (quotient rule) followed by solving a linear equation. The base-3 logarithm adds minimal complexity since students simply apply log laws mechanically then convert to exponential form. Slightly easier than average due to the direct single-technique approach with no conceptual obstacles. |
| Spec | 1.06f Laws of logarithms: addition, subtraction, power rules1.06g Equations with exponentials: solve a^x = b |
| Answer | Marks | Guidance |
|---|---|---|
| \(\log_3(12y+5) - \log_3(1-3y) = 2 \Rightarrow \log_3\frac{12y+5}{1-3y} = 2\) | B1/M1 on EPEN | Applies at least one addition or subtraction law of logs correctly. Can also be awarded for using \(2 = \log_3 9\) |
| \(\log_3\frac{12y+5}{1-3y} = 2 \Rightarrow \frac{12y+5}{1-3y} = 3^2 \Rightarrow 9 - 27y = 12y + 5 \Rightarrow y = \ldots\) | M1 | Rigorous argument with no incorrect working to remove the log(s) correctly and obtain a correct equation, then solve for \(y\) |
| \(y = \frac{4}{39}\) | A1 | Correct exact value. Allow equivalent fractions. |
## Question 3:
$\log_3(12y+5) - \log_3(1-3y) = 2 \Rightarrow \log_3\frac{12y+5}{1-3y} = 2$ | B1/M1 on EPEN | Applies at least one addition or subtraction law of logs correctly. Can also be awarded for using $2 = \log_3 9$
$\log_3\frac{12y+5}{1-3y} = 2 \Rightarrow \frac{12y+5}{1-3y} = 3^2 \Rightarrow 9 - 27y = 12y + 5 \Rightarrow y = \ldots$ | M1 | Rigorous argument with no incorrect working to remove the log(s) correctly and obtain a correct equation, then solve for $y$
$y = \frac{4}{39}$ | A1 | Correct exact value. Allow equivalent fractions.
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\begin{enumerate}
\item Using the laws of logarithms, solve the equation
\end{enumerate}
$$\log _ { 3 } ( 12 y + 5 ) - \log _ { 3 } ( 1 - 3 y ) = 2$$
\hfill \mbox{\textit{Edexcel Paper 2 2021 Q3 [3]}}