Edexcel Paper 1 2023 June — Question 10 9 marks

Exam BoardEdexcel
ModulePaper 1 (Paper 1)
Year2023
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircles
TypeRange of parameter for intersection
DifficultyStandard +0.8 This question requires completing the square to find centre and radius (standard technique), then substituting the line equation into the circle to form a quadratic, and using the discriminant condition for two distinct intersections. The algebraic manipulation with parameter k throughout, particularly in part (b), elevates this above a routine question but remains within typical A-level problem-solving scope.
Spec1.03d Circles: equation (x-a)^2+(y-b)^2=r^21.03e Complete the square: find centre and radius of circle

  1. A circle \(C\) has equation
$$x ^ { 2 } + y ^ { 2 } + 6 k x - 2 k y + 7 = 0$$ where \(k\) is a constant.
  1. Find in terms of \(k\),
    1. the coordinates of the centre of \(C\)
    2. the radius of \(C\) The line with equation \(y = 2 x - 1\) intersects \(C\) at 2 distinct points.
  2. Find the range of possible values of \(k\).

Question 10:
Part (a)(i):
AnswerMarks Guidance
AnswerMark Guidance
Centre \((-3k, k)\)B1 May be written as \(x = -3k\), \(y = k\). Accept without brackets.
Part (a)(ii):
AnswerMarks Guidance
AnswerMark Guidance
\((x+3k)^2 - 9k^2 + (y-k)^2 - k^2 + 7 = 0 \Rightarrow (x+3k)^2 + (y-k)^2 = \ldots\)M1 Attempts to find \(r^2\) by completing the square and collecting terms. Alternatively may use \(x^2 + y^2 + 2fx + 2gy + c = 0 \Rightarrow r^2 = f^2 + g^2 - c\)
Radius \(\sqrt{10k^2 - 7}\)A1ft Condone unsimplified equivalents such as \(\sqrt{9k^2 + k^2 - 7}\). Must be extracted and explicitly written. Only follow through on centre of form \((\pm 3k, \pm k)\). Do not allow \(\pm\sqrt{10k^2-7}\).
Part (b):
AnswerMarks Guidance
AnswerMark Guidance
\(x^2 + (2x-1)^2 + 6kx - 2k(2x-1) + 7 = 0 \Rightarrow \ldots x^2 + (pk+q)x + rk + s(=0)\)M1 Substitutes \(y = 2x - 1\) into equation of circle and attempts to collect terms
\(5x^2 + (2k-4)x + 2k + 8\ (= 0)\)A1 Check carefully signs of \(2k-4\) since \(4-2k\) will lead to same answers and should score maximum M1A0dM1A0ddM1A0
\((2k-4)^2 - 4 \times 5 \times (2k+8) = 0 \Rightarrow k = \ldots\)dM1 Attempts to find \(b^2 - 4ac\) for their 3TQ and attempts to find at least one critical value
Critical values \(= 7 \pm \sqrt{85}\)A1 \(7 \pm \sqrt{85}\)
\(k <\) "\(7 - \sqrt{85}\)" or \(k >\) "\(7 + \sqrt{85}\)" o.e.ddM1 Attempts to find outside region for their critical values. Must have two values. Condone \(k \geq\) "\(7+\sqrt{85}\)", \(k \leq\) "\(7-\sqrt{85}\)". Dependent on previous two method marks.
\(k < 7 - \sqrt{85}\) or \(k > 7 + \sqrt{85}\) o.e.A1 Allow equivalent expressions including set notation for both outside regions. Allow ",", "or", "\(\cup\)" or space between answers. Do not accept "and", "\(\cap\)". If a variable is used it must be in terms of \(k\).
## Question 10:

### Part (a)(i):

| Answer | Mark | Guidance |
|--------|------|----------|
| Centre $(-3k, k)$ | B1 | May be written as $x = -3k$, $y = k$. Accept without brackets. |

### Part (a)(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| $(x+3k)^2 - 9k^2 + (y-k)^2 - k^2 + 7 = 0 \Rightarrow (x+3k)^2 + (y-k)^2 = \ldots$ | M1 | Attempts to find $r^2$ by completing the square and collecting terms. Alternatively may use $x^2 + y^2 + 2fx + 2gy + c = 0 \Rightarrow r^2 = f^2 + g^2 - c$ |
| Radius $\sqrt{10k^2 - 7}$ | A1ft | Condone unsimplified equivalents such as $\sqrt{9k^2 + k^2 - 7}$. Must be extracted and explicitly written. Only follow through on centre of form $(\pm 3k, \pm k)$. Do not allow $\pm\sqrt{10k^2-7}$. |

### Part (b):

| Answer | Mark | Guidance |
|--------|------|----------|
| $x^2 + (2x-1)^2 + 6kx - 2k(2x-1) + 7 = 0 \Rightarrow \ldots x^2 + (pk+q)x + rk + s(=0)$ | M1 | Substitutes $y = 2x - 1$ into equation of circle and attempts to collect terms |
| $5x^2 + (2k-4)x + 2k + 8\ (= 0)$ | A1 | Check carefully signs of $2k-4$ since $4-2k$ will lead to same answers and should score maximum M1A0dM1A0ddM1A0 |
| $(2k-4)^2 - 4 \times 5 \times (2k+8) = 0 \Rightarrow k = \ldots$ | dM1 | Attempts to find $b^2 - 4ac$ for their 3TQ and attempts to find at least one critical value |
| Critical values $= 7 \pm \sqrt{85}$ | A1 | $7 \pm \sqrt{85}$ |
| $k <$ "$7 - \sqrt{85}$" or $k >$ "$7 + \sqrt{85}$" o.e. | ddM1 | Attempts to find outside region for their critical values. Must have two values. Condone $k \geq$ "$7+\sqrt{85}$", $k \leq$ "$7-\sqrt{85}$". Dependent on previous two method marks. |
| $k < 7 - \sqrt{85}$ or $k > 7 + \sqrt{85}$ o.e. | A1 | Allow equivalent expressions including set notation for both outside regions. Allow ",", "or", "$\cup$" or space between answers. Do not accept "and", "$\cap$". If a variable is used it must be in terms of $k$. |

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\begin{enumerate}
  \item A circle $C$ has equation
\end{enumerate}

$$x ^ { 2 } + y ^ { 2 } + 6 k x - 2 k y + 7 = 0$$

where $k$ is a constant.\\
(a) Find in terms of $k$,\\
(i) the coordinates of the centre of $C$\\
(ii) the radius of $C$

The line with equation $y = 2 x - 1$ intersects $C$ at 2 distinct points.\\
(b) Find the range of possible values of $k$.

\hfill \mbox{\textit{Edexcel Paper 1 2023 Q10 [9]}}