| Exam Board | Edexcel |
|---|---|
| Module | AS Paper 2 (AS Paper 2) |
| Year | 2023 |
| Session | June |
| Marks | 5 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Measures of Location and Spread |
| Type | Forward transformation: find new statistics |
| Difficulty | Moderate -0.8 This is a routine AS-level statistics question testing standard procedures: reading from a histogram, verifying a given mean calculation, computing standard deviation from grouped data, and applying the conceptual understanding that subtracting a constant affects the mean but not the standard deviation. All steps are algorithmic with no problem-solving or novel insight required. |
| Spec | 2.02b Histogram: area represents frequency2.02f Measures of average and spread2.02g Calculate mean and standard deviation |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(61\times(2\times3),\quad 63\times(2\times12),\quad 65\times(2\times8),\quad 67\times(2\times2)\) | M1 | At least 3 correct products seen (oe). Allow any 3 from 366, 1512, 1040, 268 |
| \(\frac{61\times(2\times3)+63\times(2\times12)+65\times(2\times8)+67\times(2\times2)}{50}=63.72^*\) | A1*cso | Correct expression for mean (may be seen in stages) and given answer. \(\frac{3186}{50}=63.72\) on its own is M0A0, but following all 4 correct products can score M1A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(\sqrt{\frac{61^2\times6+63^2\times24+65^2\times16+67^2\times4}{50}-63.72^2}\) | M1 | Correct expression for standard deviation including root. Allow equivalent complete methods. NB: \(\sum fx^2 = 203138\) |
| \(=\sqrt{2.5216}=1.58795\ldots\quad=\text{awrt } \mathbf{1.59}\) | A1 | awrt 1.59 (allow \(s=\) awrt 1.60). Correct answer with no incorrect working scores 2 out of 2 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| No effect (oe) since, e.g.: adding/subtracting does not affect the standard deviation (only multiplication and division do); the weights will have the same spread; the distance of each weight from the mean will not have changed; they all change by the same amount | B1 | Correct statement and correct explanation |
## Question 1:
### Part (a)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $61\times(2\times3),\quad 63\times(2\times12),\quad 65\times(2\times8),\quad 67\times(2\times2)$ | M1 | At least 3 correct products seen (oe). Allow any 3 from 366, 1512, 1040, 268 |
| $\frac{61\times(2\times3)+63\times(2\times12)+65\times(2\times8)+67\times(2\times2)}{50}=63.72^*$ | A1*cso | Correct expression for mean (may be seen in stages) and given answer. $\frac{3186}{50}=63.72$ on its own is M0A0, but following all 4 correct products can score M1A1 |
**SC:** **B2:** $\frac{61\times3+63\times12+65\times8+67\times2}{25}=63.72^*$ scores M1A1 on epen
**(2 marks)**
---
### Part (b)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\sqrt{\frac{61^2\times6+63^2\times24+65^2\times16+67^2\times4}{50}-63.72^2}$ | M1 | Correct expression for standard deviation including root. Allow equivalent complete methods. NB: $\sum fx^2 = 203138$ |
| $=\sqrt{2.5216}=1.58795\ldots\quad=\text{awrt } \mathbf{1.59}$ | A1 | awrt 1.59 (allow $s=$ awrt 1.60). Correct answer with no incorrect working scores 2 out of 2 |
**SC:** **B2:** $\sqrt{\frac{61^2\times3+63^2\times12+65^2\times8+67^2\times2}{25}-63.72^2}=\text{awrt }1.59$ scores M1A1 on epen
**(2 marks)**
---
### Part (c)
| Answer/Working | Marks | Guidance |
|---|---|---|
| No effect (oe) since, e.g.: adding/subtracting does not affect the standard deviation (only multiplication and division do); the weights will have the same spread; the distance of each weight from the mean will not have changed; they all change by the same amount | B1 | Correct statement **and** correct explanation |
**(1 mark)**
**Total: 5 marks**
\begin{enumerate}
\item The histogram and its frequency polygon below give information about the weights, in grams, of 50 plums.\\
\includegraphics[max width=\textwidth, alt={}, center]{854568d2-b32d-44de-8a9c-26372e509c20-02_908_1307_328_386}\\
(a) Show that an estimate for the mean weight of the 50 plums is 63.72 grams.\\
(b) Calculate an estimate for the standard deviation of the 50 plums.
\end{enumerate}
Later it was discovered that the scales used to weigh the plums were broken.\\
Each plum actually weighs 5 grams less than originally thought.\\
(c) State the effect this will have on the estimate of the standard deviation in part (b). Give a reason for your answer.
\hfill \mbox{\textit{Edexcel AS Paper 2 2023 Q1 [5]}}