CAIE P3 2015 November — Question 10 10 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2015
SessionNovember
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration by Substitution
TypeFinding maximum/minimum on curve
DifficultyStandard +0.8 This question requires finding a maximum using quotient rule differentiation and solving a cubic equation, then integration by substitution with u = 1 + x³ to find area and solve ln(1+p³)/3 = 1 for p. The substitution is non-trivial but recognizable, and solving for p requires algebraic manipulation of logarithms. More challenging than routine calculus but within standard P3 scope.
Spec1.07n Stationary points: find maxima, minima using derivatives1.08e Area between curve and x-axis: using definite integrals

10 \includegraphics[max width=\textwidth, alt={}, center]{efa44efb-9350-4d54-b5e1-4f722781a5f3-3_366_764_1914_687} The diagram shows the curve \(y = \frac { x ^ { 2 } } { 1 + x ^ { 3 } }\) for \(x \geqslant 0\), and its maximum point \(M\). The shaded region \(R\) is enclosed by the curve, the \(x\)-axis and the lines \(x = 1\) and \(x = p\).
  1. Find the exact value of the \(x\)-coordinate of \(M\).
  2. Calculate the value of \(p\) for which the area of \(R\) is equal to 1 . Give your answer correct to 3 significant figures.

Question 10:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Use the quotient ruleM1
Obtain correct derivative in any formA1
Equate derivative to zero and solve for \(x\)M1
Obtain answer \(x = \sqrt[3]{2}\), or exact equivalentA1 [4]
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
State or imply indefinite integral is of the form \(k\ln(1+x^3)\)M1
State indefinite integral \(\frac{1}{3}\ln(1+x^3)\)A1
Substitute limits correctly in an integral of the form \(k\ln(1+x^3)\)M1
State or imply that the area of \(R\) is equal to \(\frac{1}{3}\ln(1+p^3) - \frac{1}{3}\ln 2\), or equivalentA1
Use a correct method for finding \(p\) from an equation of the form \(\ln(1+p^3) = a\) or \(\ln((1+p^3)/2) = b\)M1
Obtain answer \(p = 3.40\)A1 [2]
## Question 10:

### Part (i):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Use the quotient rule | **M1** | |
| Obtain correct derivative in any form | **A1** | |
| Equate derivative to zero and solve for $x$ | **M1** | |
| Obtain answer $x = \sqrt[3]{2}$, or exact equivalent | **A1** | [4] |

### Part (ii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| State or imply indefinite integral is of the form $k\ln(1+x^3)$ | **M1** | |
| State indefinite integral $\frac{1}{3}\ln(1+x^3)$ | **A1** | |
| Substitute limits correctly in an integral of the form $k\ln(1+x^3)$ | **M1** | |
| State or imply that the area of $R$ is equal to $\frac{1}{3}\ln(1+p^3) - \frac{1}{3}\ln 2$, or equivalent | **A1** | |
| Use a correct method for finding $p$ from an equation of the form $\ln(1+p^3) = a$ or $\ln((1+p^3)/2) = b$ | **M1** | |
| Obtain answer $p = 3.40$ | **A1** | [2] |
10\\
\includegraphics[max width=\textwidth, alt={}, center]{efa44efb-9350-4d54-b5e1-4f722781a5f3-3_366_764_1914_687}

The diagram shows the curve $y = \frac { x ^ { 2 } } { 1 + x ^ { 3 } }$ for $x \geqslant 0$, and its maximum point $M$. The shaded region $R$ is enclosed by the curve, the $x$-axis and the lines $x = 1$ and $x = p$.\\
(i) Find the exact value of the $x$-coordinate of $M$.\\
(ii) Calculate the value of $p$ for which the area of $R$ is equal to 1 . Give your answer correct to 3 significant figures.

\hfill \mbox{\textit{CAIE P3 2015 Q10 [10]}}
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