OCR MEI D2 2014 June — Question 1 16 marks

Exam BoardOCR MEI
ModuleD2 (Decision Mathematics 2)
Year2014
SessionJune
Marks16
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModelling and Hypothesis Testing
TypeInsurance and risk mitigation decisions
DifficultyModerate -0.8 This is a straightforward decision mathematics question requiring standard techniques: drawing decision trees, calculating EMV (expected monetary value), finding break-even probabilities, and applying a simple utility function. All parts follow textbook procedures with no novel problem-solving required. The calculations are routine (e.g., 0.0002 × 400000 = 80 < 100), and the conceptual understanding needed is basic. This is easier than average A-level material due to its mechanical nature and clear structure.
Spec5.01a Permutations and combinations: evaluate probabilities5.01b Selection/arrangement: probability problems

1 Keith is wondering whether or not to insure the value of his house against destruction. His friend Georgia has told him that it is a waste of money. Georgia argues that the insurance company sets its premiums (how much it charges for insurance) to take account of the probability of destruction, plus an extra fee for its profit. Georgia argues that house-owners are, on average, simply paying fees to the insurance company. Keith's house is valued at \(\pounds 400000\). The annual premium for insuring its value against destruction is \(\pounds 100\). Past statistics show that the probability of destruction in any one year is 0.0002 .
  1. Draw a decision tree to model Keith's decision and the possible outcomes.
  2. Compute Keith's EMV and give the course of action which corresponds to that EMV.
  3. What would be the insurance premium if there were no fee for the insurance company? For the remainder of the question the insurance premium is still \(\pounds 100\).
    Suppose that, instead of EMV, Keith uses the utility function utility \(= ( \text { money } ) ^ { 0.5 }\).
  4. Compute Keith's utility and give his corresponding course of action. Keith suspects that it may be the case that he lives in an area in which the probability of destruction in a given year, \(p\), is not 0.0002 .
  5. Draw a decision tree, using the EMV criterion, to model Keith's decision in terms of \(p\), the probability of destruction in the area in which Keith lives.
  6. Find the value of \(p\) which would make it worthwhile for Keith to insure his house using the EMV criterion.
  7. Explain why Keith may wish to insure even if \(p\) is less than the value which you found in part (vi). [1]
    (a) A national Sunday newspaper runs a "You are the umpire" series, in which questions are posed about whether a batsman in cricket is given "out", and why, or "not out". One Sunday the readers were told that a ball had either hit the bat and then the pad, or had missed the bat and hit the pad; the umpire could not be sure which. The ball had then flown directly to a fielder, who had caught it. The LBW (leg before wicket) rule is complicated. The readers were told that this batsman should be given out (LBW) if the ball had not hit the bat. On the other hand, if the ball had hit the bat, then he should be given out (caught). Readers were asked what the decision should be. The answer given in the newspaper was that this batsman should be given not out because the umpire could not be sure that the batsman was out (LBW), and could not be sure that he was out (caught).

Question 1:
(i) & (ii)
AnswerMarks Guidance
AnswerMarks Guidance
Decision node drawn correctlyM1 Decision node
Tree with labels shownA1 (with labels)
Insure chance nodes drawnM1 insure chance nodes
Labels shown (can show just one arc)A1 (with labels)
\(\sim\)insure chance node drawnM1 \(\sim\)insure chance node
Labels shown: £399920, £400000A1 (with labels)
EMV is £399920, by not insuringB1 EMV
Course of action statedB1 course of action
[8]
(iii)
AnswerMarks Guidance
AnswerMarks Guidance
£80B1
[1]
(iv)
AnswerMarks Guidance
AnswerMarks Guidance
Insuring has utility \(\sqrt{399900} = 632.3765\); Not insuring has utility \(0.9998 \times \sqrt{400000} = 632.329\)M1 \(\text{prob} \times \sqrt{\text{value}}\) not \(\sqrt{\text{prob} \times \text{value}}\)
Both utilities calculated (cao)A1 both utilities (cao)
So utility is maximised by insuringB1 www
[3]
(v)
AnswerMarks Guidance
AnswerMarks Guidance
\(p\) used on \(\sim\)insure branch of treeB1 \(p\) used on \(\sim\)insure branch
[1]
(vi)
AnswerMarks Guidance
AnswerMarks Guidance
Condition: \(399900 > 400000(1-p)\)M1
i.e. \(p > 0.00025\)A1 cao
[2]
(vii)
AnswerMarks Guidance
AnswerMarks Guidance
EMV analysis does not take adequate account of the loss caused by destruction. That is why the concept of utility is needed.B1
[1]
## Question 1:

**(i) & (ii)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| Decision node drawn correctly | M1 | Decision node |
| Tree with labels shown | A1 | (with labels) |
| Insure chance nodes drawn | M1 | insure chance nodes |
| Labels shown (can show just one arc) | A1 | (with labels) |
| $\sim$insure chance node drawn | M1 | $\sim$insure chance node |
| Labels shown: £399920, £400000 | A1 | (with labels) |
| EMV is £399920, by not insuring | B1 | EMV |
| Course of action stated | B1 | course of action |
| **[8]** | | |

**(iii)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| £80 | B1 | |
| **[1]** | | |

**(iv)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| Insuring has utility $\sqrt{399900} = 632.3765$; Not insuring has utility $0.9998 \times \sqrt{400000} = 632.329$ | M1 | $\text{prob} \times \sqrt{\text{value}}$ not $\sqrt{\text{prob} \times \text{value}}$ |
| Both utilities calculated (cao) | A1 | both utilities (cao) |
| So utility is maximised by insuring | B1 | www |
| **[3]** | | |

**(v)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| $p$ used on $\sim$insure branch of tree | B1 | $p$ used on $\sim$insure branch |
| **[1]** | | |

**(vi)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| Condition: $399900 > 400000(1-p)$ | M1 | |
| i.e. $p > 0.00025$ | A1 | cao |
| **[2]** | | |

**(vii)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| EMV analysis does not take adequate account of the loss caused by destruction. That is why the concept of utility is needed. | B1 | |
| **[1]** | | |

---
1 Keith is wondering whether or not to insure the value of his house against destruction. His friend Georgia has told him that it is a waste of money. Georgia argues that the insurance company sets its premiums (how much it charges for insurance) to take account of the probability of destruction, plus an extra fee for its profit. Georgia argues that house-owners are, on average, simply paying fees to the insurance company.

Keith's house is valued at $\pounds 400000$. The annual premium for insuring its value against destruction is $\pounds 100$. Past statistics show that the probability of destruction in any one year is 0.0002 .\\
(i) Draw a decision tree to model Keith's decision and the possible outcomes.\\
(ii) Compute Keith's EMV and give the course of action which corresponds to that EMV.\\
(iii) What would be the insurance premium if there were no fee for the insurance company?

For the remainder of the question the insurance premium is still $\pounds 100$.\\
Suppose that, instead of EMV, Keith uses the utility function utility $= ( \text { money } ) ^ { 0.5 }$.\\
(iv) Compute Keith's utility and give his corresponding course of action.

Keith suspects that it may be the case that he lives in an area in which the probability of destruction in a given year, $p$, is not 0.0002 .\\
(v) Draw a decision tree, using the EMV criterion, to model Keith's decision in terms of $p$, the probability of destruction in the area in which Keith lives.\\
(vi) Find the value of $p$ which would make it worthwhile for Keith to insure his house using the EMV criterion.\\
(vii) Explain why Keith may wish to insure even if $p$ is less than the value which you found in part (vi). [1]\\
(a) A national Sunday newspaper runs a "You are the umpire" series, in which questions are posed about whether a batsman in cricket is given "out", and why, or "not out". One Sunday the readers were told that a ball had either hit the bat and then the pad, or had missed the bat and hit the pad; the umpire could not be sure which. The ball had then flown directly to a fielder, who had caught it.

The LBW (leg before wicket) rule is complicated. The readers were told that this batsman should be given out (LBW) if the ball had not hit the bat. On the other hand, if the ball had hit the bat, then he should be given out (caught). Readers were asked what the decision should be.

The answer given in the newspaper was that this batsman should be given not out because the umpire could not be sure that the batsman was out (LBW), and could not be sure that he was out (caught).\\

\hfill \mbox{\textit{OCR MEI D2 2014 Q1 [16]}}