| Exam Board | OCR |
|---|---|
| Module | D2 (Decision Mathematics 2) |
| Year | 2013 |
| Session | June |
| Marks | 19 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Combinations & Selection |
| Type | Basic committee/group selection |
| Difficulty | Moderate -1.0 This is a straightforward game theory question requiring basic understanding of zero-sum games, dominance, and play-safe strategies. The calculations involve simple arithmetic and finding row/column maxima/minima. While it has multiple parts, each step is routine application of standard Decision Mathematics techniques with no novel problem-solving required. |
| Spec | 7.08a Pay-off matrix: zero-sum games7.08b Dominance: reduce pay-off matrix7.08c Pure strategies: play-safe strategies and stable solutions7.08d Nash equilibrium: identification and interpretation |
| Collies | |||||
| \cline { 2 - 6 } | \(W\) | \(X\) | \(Y\) | \(Z\) | |
| \cline { 2 - 6 } | \(P\) | 1 | 2 | - 1 | 3 |
| \cline { 2 - 6 } | \(Q\) | - 2 | 1 | - 3 | - 1 |
| \(R\) | 2 | - 4 | 1 | 0 | |
| \cline { 2 - 6 } | |||||
| \cline { 2 - 6 } | |||||
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| Correct structure with directed arcs labelled \(A, B, C, \ldots\) | M1 | Correct structure, even with unnecessary dummies and no directions |
| Correct structure with no unnecessary dummies, directed arcs labelled \(A, B, C, \ldots\) | A1 | |
| Forward pass with at most 1 independent error | M1 | Follow through their network if possible |
| Backward pass with at most 1 independent error | M1 | |
| Both passes correct for their (non trivial) network and correct durations | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| Minimum project completion time \(= 80\) mins | B1 | 80 minutes (cao), condone omission of units |
| Critical activities: \(B, C, E, H\) | B1 | \(B, C, E, H\) (cao) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(B\ | A\ | A\ |
| All activities accounted for, precedences correct and duration \(= 80\) | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| Schedule with \(B, A, E, F, H\) with \(B\) first, all activities accounted for, precedences correct and duration \(= 85\) | M1, A1 | Molly does \(B, A, E, F, H\) with \(B\) first; all activities accounted for, precedences correct and duration \(= 85\) |
# Question 3:
## Parts (i) and (ii)
| Answer | Marks | Guidance |
|--------|-------|----------|
| Correct structure with directed arcs labelled $A, B, C, \ldots$ | M1 | Correct structure, even with unnecessary dummies and no directions |
| Correct structure with no unnecessary dummies, directed arcs labelled $A, B, C, \ldots$ | A1 | |
| Forward pass with at most 1 independent error | M1 | Follow through their network if possible |
| Backward pass with at most 1 independent error | M1 | |
| Both passes correct for their (non trivial) network and correct durations | A1 | |
## Part (iii)
| Answer | Marks | Guidance |
|--------|-------|----------|
| Minimum project completion time $= 80$ mins | B1 | 80 minutes (cao), condone omission of units |
| Critical activities: $B, C, E, H$ | B1 | $B, C, E, H$ (cao) |
## Part (iv)
| Answer | Marks | Guidance |
|--------|-------|----------|
| $B\|A\|A\|D\|D\|D\|F\|H\|H\|H\|H\|H\|H$ with $C\|C\|C\|C\|G\|G\|G$ and $E\|E\|E\|E\|E$ | M1 | Molly does $B, A, F, H$ with $B$ first |
| All activities accounted for, precedences correct and duration $= 80$ | A1 | |
## Part (v)
| Answer | Marks | Guidance |
|--------|-------|----------|
| Schedule with $B, A, E, F, H$ with $B$ first, all activities accounted for, precedences correct and duration $= 85$ | M1, A1 | Molly does $B, A, E, F, H$ with $B$ first; all activities accounted for, precedences correct and duration $= 85$ |
---
3 The 'Rovers' and the 'Collies' are two teams of dog owners who compete in weekly dog shows. The top three dogs owned by members of the Rovers are Prince, Queenie and Rex. The top four dogs owned by the Collies are Woof, Xena, Yappie and Zulu.
In a show the Rovers choose one of their dogs to compete against one of the dogs owned by the Collies. There are 10 points available in total. Each of the 10 points is awarded either to the dog owned by the Rovers or to the dog owned by the Collies. There are no tied points. At the end of the competition, 5 points are subtracted from the number of points won by each dog to give the score for that dog.
The table shows the score for the dog owned by the Rovers for each combination of dogs.
\begin{center}
\begin{tabular}{ l | r | r | r | r | r | }
& \multicolumn{5}{c}{Collies} \\
\cline { 2 - 6 }
& & $W$ & \multicolumn{1}{|c|}{$X$} & $Y$ & $Z$ \\
\cline { 2 - 6 }
& $P$ & 1 & 2 & - 1 & 3 \\
\cline { 2 - 6 }
& $Q$ & - 2 & 1 & - 3 & - 1 \\
\hline
$R$ & 2 & - 4 & 1 & 0 & \\
\cline { 2 - 6 }
& & & & & \\
\cline { 2 - 6 }
\end{tabular}
\end{center}
(i) Explain why calculating the score by subtracting 5 from the number of points for each dog makes this a zero-sum game.\\
(ii) If the Rovers choose Prince and the Collies choose Woof, what score does Woof get, and how many points do Prince and Woof each get in the competition?\\
(iii) Show that column $W$ is dominated by one of the other columns, and state which column this is.\\
(iv) Delete the column for $W$ and find the play-safe strategy for the Rovers and the play-safe strategy for the Collies on the table that remains.
Queenie is ill one week, so the Rovers make a random choice between Prince and Rex, choosing Prince with probability $p$ and Rex with probability $1 - p$.\\
(v) Write down and simplify an expression for the expected score for the Rovers when the Collies choose Xena. Write down and simplify the corresponding expressions for when the Collies choose Yappie and for when they choose Zulu.\\
(vi) Using graph paper, draw a graph to show the expected score for the Rovers against $p$ for each of the choices that the Collies can make. Using your graph, find the optimal value of $p$ for the Rovers.
If Queenie had not been ill, the Rovers would have made a random choice between Prince, Queenie and Rex, choosing Prince with probability $p _ { 1 }$, Queenie with probability $p _ { 2 }$ and Rex with probability $p _ { 3 }$.
The problem of choosing the optimal values of $p _ { 1 } , p _ { 2 }$ and $p _ { 3 }$ can be formulated as the following linear programming problem:
$$\begin{array} { l l }
\operatorname { maximise } & M = m - 4 \\
\text { subject to } & m \leqslant 6 p _ { 1 } + 5 p _ { 2 } , \\
& m \leqslant 3 p _ { 1 } + p _ { 2 } + 5 p _ { 3 } , \\
& m \leqslant 7 p _ { 1 } + 3 p _ { 2 } + 4 p _ { 3 } , \\
& p _ { 1 } + p _ { 2 } + p _ { 3 } \leqslant 1 \\
\text { and } & p _ { 1 } \geqslant 0 , p _ { 2 } \geqslant 0 , p _ { 3 } \geqslant 0 , m \geqslant 0 .
\end{array}$$
(vii) Explain how the expressions $6 p _ { 1 } + 5 p _ { 2 } , 3 p _ { 1 } + p _ { 2 } + 5 p _ { 3 }$ and $7 p _ { 1 } + 3 p _ { 2 } + 4 p _ { 3 }$ were obtained. Also explain how the linear programming formulation tells you that $M$ is a maximin solution.
The Simplex algorithm is used to find the optimal values of the probabilities. The optimal value of $p _ { 1 }$ is $\frac { 5 } { 8 }$ and the optimal value of $p _ { 2 }$ is 0 .\\
(viii) Calculate the optimal value of $p _ { 3 }$ and the corresponding value of $M$.
\hfill \mbox{\textit{OCR D2 2013 Q3 [19]}}