CAIE P1 2021 November — Question 4 6 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2021
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeMixed arithmetic and geometric
DifficultyStandard +0.3 This question requires applying standard formulas for sum to infinity of a GP and sum of n terms of an AP, then solving a linear equation. Part (b) is straightforward substitution into the nth term formula. While it involves two progressions, the required techniques are routine and the algebra is simple, making it slightly easier than average.
Spec1.04h Arithmetic sequences: nth term and sum formulae1.04i Geometric sequences: nth term and finite series sum1.04j Sum to infinity: convergent geometric series |r|<1

4 The first term of an arithmetic progression is \(a\) and the common difference is - 4 . The first term of a geometric progression is \(5 a\) and the common ratio is \(- \frac { 1 } { 4 }\). The sum to infinity of the geometric progression is equal to the sum of the first eight terms of the arithmetic progression.
  1. Find the value of \(a\).
    The \(k\) th term of the arithmetic progression is zero.
  2. Find the value of \(k\).

Question 4(a):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{5a}{1-(\pm\frac{1}{4})}\)B1 Use of correct formula for sum to infinity.
\(\frac{8}{2}[2a + 7(-4)]\)\*M1 Use of correct formula for sum of 8 terms and form equation; allow 1 error.
\(4a = 8a - 112\) leading to \(a = [28]\)DM1 Solve equation to reach a value of \(a\).
\(a = 28\)A1 Correct value.
Question 4(b):
AnswerMarks Guidance
AnswerMarks Guidance
\(their\ 28 + (k-1)(-4) = 0\)M1 Use of correct method with *their* \(a\).
\([k =]\ 8\)A1
## Question 4(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{5a}{1-(\pm\frac{1}{4})}$ | B1 | Use of correct formula for sum to infinity. |
| $\frac{8}{2}[2a + 7(-4)]$ | \*M1 | Use of correct formula for sum of 8 terms and form equation; allow 1 error. |
| $4a = 8a - 112$ leading to $a = [28]$ | DM1 | Solve equation to reach a value of $a$. |
| $a = 28$ | A1 | Correct value. |

## Question 4(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $their\ 28 + (k-1)(-4) = 0$ | M1 | Use of correct method with *their* $a$. |
| $[k =]\ 8$ | A1 | |

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4 The first term of an arithmetic progression is $a$ and the common difference is - 4 . The first term of a geometric progression is $5 a$ and the common ratio is $- \frac { 1 } { 4 }$. The sum to infinity of the geometric progression is equal to the sum of the first eight terms of the arithmetic progression.
\begin{enumerate}[label=(\alph*)]
\item Find the value of $a$.\\

The $k$ th term of the arithmetic progression is zero.
\item Find the value of $k$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2021 Q4 [6]}}