CAIE P3 2014 November — Question 8 9 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2014
SessionNovember
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeDerive triple angle then solve equation
DifficultyStandard +0.3 This is a structured multi-part question with clear guidance at each step. Part (i) is a standard derivation using addition formulae and double angle identities. Part (ii) involves algebraic substitution following explicit instructions. Part (iii) requires solving a trigonometric equation and back-substituting. While it requires multiple techniques and careful algebra, the question provides substantial scaffolding and uses well-practiced methods, making it slightly easier than the average A-level question.
Spec1.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

8
  1. By first expanding \(\sin ( 2 \theta + \theta )\), show that $$\sin 3 \theta = 3 \sin \theta - 4 \sin ^ { 3 } \theta$$
  2. Show that, after making the substitution \(x = \frac { 2 \sin \theta } { \sqrt { 3 } }\), the equation \(x ^ { 3 } - x + \frac { 1 } { 6 } \sqrt { } 3 = 0\) can be written in the form \(\sin 3 \theta = \frac { 3 } { 4 }\).
  3. Hence solve the equation $$x ^ { 3 } - x + \frac { 1 } { 6 } \sqrt { } 3 = 0$$ giving your answers correct to 3 significant figures.

AnswerMarks Guidance
(i) Use \(\sin(A + B)\) formula to express \(\sin 3\theta\) in terms of trig. functions of \(2\theta\) and \(\theta\)M1
Use correct double angle formulae and Pythagoras to express \(\sin 3\theta\) in terms of \(\sin\theta\)M1
Obtain a correct expression in terms of \(\sin\theta\) in any formA1
Obtain the given identityA1 [4]
[SR: Give M1 for using correct formulae to express RHS in terms of \(\sin\theta\) and \(\cos 2\theta\), then M1A1 for expressing in terms of \(\sin\theta\) and \(\sin 3\theta\) only, or in terms of \(\cos\theta, \sin\theta, \cos 2\theta\) and \(\sin 2\theta\), then A1 for obtaining the given identity.]
AnswerMarks Guidance
(ii) Substitute for \(x\) and obtain the given answerB1 [1]
(iii) Carry out a correct method to find a value of \(x\)M1
Obtain answers 0.322, 0.799, −1.12A1 + A1 + A1 [4]
[Solutions with more than 3 answers can only earn a maximum of A1 + A1.]
**(i)** Use $\sin(A + B)$ formula to express $\sin 3\theta$ in terms of trig. functions of $2\theta$ and $\theta$ | M1 |
Use correct double angle formulae and Pythagoras to express $\sin 3\theta$ in terms of $\sin\theta$ | M1 |
Obtain a correct expression in terms of $\sin\theta$ in any form | A1 |
Obtain the given identity | A1 | [4]
**[SR: Give M1 for using correct formulae to express RHS in terms of $\sin\theta$ and $\cos 2\theta$, then M1A1 for expressing in terms of $\sin\theta$ and $\sin 3\theta$ only, or in terms of $\cos\theta, \sin\theta, \cos 2\theta$ and $\sin 2\theta$, then A1 for obtaining the given identity.]**

**(ii)** Substitute for $x$ and obtain the given answer | B1 | [1]

**(iii)** Carry out a correct method to find a value of $x$ | M1 |
Obtain answers 0.322, 0.799, −1.12 | A1 + A1 + A1 | [4]
**[Solutions with more than 3 answers can only earn a maximum of A1 + A1.]**
8 (i) By first expanding $\sin ( 2 \theta + \theta )$, show that

$$\sin 3 \theta = 3 \sin \theta - 4 \sin ^ { 3 } \theta$$

(ii) Show that, after making the substitution $x = \frac { 2 \sin \theta } { \sqrt { 3 } }$, the equation $x ^ { 3 } - x + \frac { 1 } { 6 } \sqrt { } 3 = 0$ can be written in the form $\sin 3 \theta = \frac { 3 } { 4 }$.\\
(iii) Hence solve the equation

$$x ^ { 3 } - x + \frac { 1 } { 6 } \sqrt { } 3 = 0$$

giving your answers correct to 3 significant figures.

\hfill \mbox{\textit{CAIE P3 2014 Q8 [9]}}