OCR D1 2010 January — Question 2

Exam BoardOCR
ModuleD1 (Decision Mathematics 1)
Year2010
SessionJanuary
TopicSequences and Series

2 A simple graph is one in which any two vertices are directly connected by at most one arc and no vertex is directly connected to itself. A connected graph is one in which every vertex is joined, directly or indirectly, to every other vertex.
A simply connected graph is one that is both simple and connected.
  1. Explain why there is no simply connected graph with exactly five vertices each of which is connected to exactly three others.
  2. A simply connected graph has five vertices \(A , B , C , D\) and \(E\), in which \(A\) has order \(4 , B\) has order 2, \(C\) has order 3, \(D\) has order 3 and \(E\) has order 2. Explain how you know that the graph is semi-Eulerian and write down a semi-Eulerian trail on this graph. A network is formed from the graph in part (ii) by weighting the arcs as given in the table below.
    \(A\)\(B\)\(C\)\(D\)\(E\)
    \(A\)-5382
    \(B\)5-6--
    \(C\)36-7-
    \(D\)8-7-9
    \(E\)2--9-
  3. Apply Prim's algorithm to the network, showing all your working, starting at vertex \(A\). Draw the resulting tree and state its total weight. A sixth vertex, \(F\), is added to the network using arcs \(C F\) and \(D F\), each of which has weight 6 .
  4. Use your answer to part (iii) to write down a lower bound for the length of the minimum tour that visits every vertex of the extended network, finishing where it starts. Apply the nearest neighbour method, starting from vertex \(A\), to find an upper bound for the length of this tour. Explain why the nearest neighbour method fails if it is started from vertex \(F\).