AQA FP3 2013 June — Question 8 19 marks

Exam BoardAQA
ModuleFP3 (Further Pure Mathematics 3)
Year2013
SessionJune
Marks19
PaperDownload PDF ↗
TopicPolar coordinates
TypeArea between two polar curves
DifficultyChallenging +1.2 This is a multi-part Further Maths polar coordinates question requiring intersection finding, distance calculations, tangency verification, and area between curves. While it involves several steps and FP3 content, each part follows standard techniques: solving r₁=r₂ for intersections, using symmetry for related points, applying the distance formula, and integrating ½r² with appropriate limits. The tangency explanation requires geometric insight but is guided by 'hence'. More routine than typical FP3 proof questions.
Spec4.09a Polar coordinates: convert to/from cartesian4.09b Sketch polar curves: r = f(theta)4.09c Area enclosed: by polar curve

8 The diagram shows a sketch of a curve and a circle. \includegraphics[max width=\textwidth, alt={}, center]{a2bc95fe-5588-4ff7-a8a3-0cd07df412c9-4_460_693_370_680} The polar equation of the curve is $$r = 3 + 2 \sin \theta , \quad 0 \leqslant \theta \leqslant 2 \pi$$ The circle, whose polar equation is \(r = 2\), intersects the curve at the points \(P\) and \(Q\), as shown in the diagram.
  1. Find the polar coordinates of \(P\) and the polar coordinates of \(Q\).
  2. A straight line, drawn from the point \(P\) through the pole \(O\), intersects the curve again at the point \(A\).
    1. Find the polar coordinates of \(A\).
    2. Find, in surd form, the length of \(A Q\).
    3. Hence, or otherwise, explain why the line \(A Q\) is a tangent to the circle \(r = 2\).
  3. Find the area of the shaded region which lies inside the circle \(r = 2\) but outside the curve \(r = 3 + 2 \sin \theta\). Give your answer in the form \(\frac { 1 } { 6 } ( m \sqrt { 3 } + n \pi )\), where \(m\) and \(n\) are integers.

8 The diagram shows a sketch of a curve and a circle.\\
\includegraphics[max width=\textwidth, alt={}, center]{a2bc95fe-5588-4ff7-a8a3-0cd07df412c9-4_460_693_370_680}

The polar equation of the curve is

$$r = 3 + 2 \sin \theta , \quad 0 \leqslant \theta \leqslant 2 \pi$$

The circle, whose polar equation is $r = 2$, intersects the curve at the points $P$ and $Q$, as shown in the diagram.
\begin{enumerate}[label=(\alph*)]
\item Find the polar coordinates of $P$ and the polar coordinates of $Q$.
\item A straight line, drawn from the point $P$ through the pole $O$, intersects the curve again at the point $A$.
\begin{enumerate}[label=(\roman*)]
\item Find the polar coordinates of $A$.
\item Find, in surd form, the length of $A Q$.
\item Hence, or otherwise, explain why the line $A Q$ is a tangent to the circle $r = 2$.
\end{enumerate}\item Find the area of the shaded region which lies inside the circle $r = 2$ but outside the curve $r = 3 + 2 \sin \theta$. Give your answer in the form $\frac { 1 } { 6 } ( m \sqrt { 3 } + n \pi )$, where $m$ and $n$ are integers.
\end{enumerate}

\hfill \mbox{\textit{AQA FP3 2013 Q8 [19]}}